[RESOLVED] Read directory, find name of last file

[Gena_Wenli]

I have a directory full of "01.xml" up to "13.xml". I need a PHP script to look at the directory (sorted alphabetically), and find the last filename. From there, I'll be fine.
Can someone help me?
Thanks!

G

[leatherback]

Something like the snip below. You'll have to add some error trapping (empty dirs etc), but I leave that as a learning exp ;-)

// open the directory
$dir = opendir($dirpath) ;

// read the files into an array
$files = readdir($dir);

reverse sort the array
rsort $files;

// get the file
$file = $files[0];

[Gena_Wenli]

I get this error:

rsort() expects parameter 1 to be array, string given

[bradgrafelman]

Looking at the manual entry for [man]rsort/man, you'll see that leatherback simply forgot some parenthesis around the array variable (probably as a result of his use of some pseudo-code).

[Gena_Wenli]

Yeah, I already caught that. But apparently adding the parenthesis doesn't solve it.

G

[leatherback]

yeah, my bad:

$files = readdir($dir);
returns only one file from the directory. Try this:

$files = array();
while (false !== ($file = readdir($dir))) 
  {
  $files[] = $file;
  }

[Weedpacket]

Or you could use [man]glob[/man].

[Gena_Wenli]

So is this the code I need?

// open the directory 
$dir = opendir('/') ; 

// read the files into an array 
$files = array(); 
while (false !== ($file = readdir($dir))) 
  { 
  $files[] = $file; 
  }

// get the file 
echo $file;

G

[Gena_Wenli]

...because I can't seem to get the code above to work.

G

[leatherback]

Why did you drop the rest of the code?

// open the directory
$dir = opendir($dirpath) ;

// read the files into an array
$files = array();
while (false !== ($file = readdir($dir)))
  {
  $files[] = $file;
  } 

//reverse sort the array
rsort($files);

// get the file
$file = $files[0]; 

[Gena_Wenli]

Oh, I see.
Thanks a lot, sorry.

G