[RESOLVED] Function as var

zzz

long day, low on caffeine...

I have a text string that has a variable inserted:

$str = 'this is my '.$var.' in my string';

I need to replace a var with an output from a function $myFunction($val1, $val2)

What's the proper syntax. I can't seem to get it right, I still need $str .

😕

NogDog

If the function returns the value via a return() statement:

$str = 'this is my '.myFunction($val1, $val2).' in my string';

If the function echoes/prints the value you want:

ob_start();
myFunction($val1, $val2);
$text = ob_get_flush();
$str = 'this is my '.$text.' in my string';

Obviously the first method is cleaner and probably quicker, so would suggest using that if possible.

zzz

Right now it echoes, so I'll go in and see if I can change to return. For some reason, when I wrote it originally it didn't work and I replaced return to echo and everything worked. Is there any reason for that?

P.S. Just tried again to replace echo to return and the function chokes. All it needs to return is a string of text...

😕

NogDog

No reason I can think of other than a logic or syntax bug. 🙂

zzz

I can't seem to see anything wrong...

NogDog

I copied and pasted your function, changed the last line to return($fullName);, and then called the function with:

echo nameProperCaps("Charles", "W.", "Reace", "first", "middle", "last")

It output "First Middle Last", which would appear to be correct?

zzz

Yes, this is what I would hope to see, but in my case I just get a blank output...

zzz

Got it to work. Not sure what it was, must've been syntax error, but it works now!