[RESOLVED] How to nest a loop inside an array?

[dmacman1962]

Hi All,

I am trying to nest a loop inside of an array, to simplify the array.

IE

The end result I want is ...

$HowManyYrs = array("" => " ", "1" => "1",  "2" => "2", "3" => "3", "4" => "4", "5" => "5", "6" => "6", "7+" => "7+");

and my 'attempt' is

$HowManyYrs = array("" => " ",
HowManyYrs .= "";
for($z = 1; $z <= 7; $z++) {
  if($z=='7') {
      $z='7+';
  }
echo '"'.$z.'" => "'.$z.'",';
 }
$HowManyYrs .= ")";

I know this is wrong, but I have tried several different approaches and non are correct.

I appreciate the help,

Don

[leatherback]

Do you want the ARRAY or the text string?

[dmacman1962]

I am trying to get an array (built dynamically) so I can build my drop down with the function I have written.

Make sense?

Thanks LB

Don

[leatherback]

yeah, makes sense.

try..

// For the header / include:
$num_options = 7;

// initialize array, with empty start option:
$HowManyYrs = array("" => " ")


for($z = 1; $z <= $num_options; $z++) 
  {
  if($z==$num_options) 
    {
     $z=$num_options.'+'; // not sure whether this is going to protest..
    }
  $HowManyYrs['$z'] = $z;
  }
echo "<pre>";
print_r($z);
echo "</pre>";

[dmacman1962]

Hmmmm..

If I use this as is it got stuck in an endless loop. So i remmed out the line below.

// For the header / include:
$num_options = 7;

// initialize array, with empty start option:
$HowManyYrs = array("" => " ");

for($z = 1; $z <= $num_options; $z++){
   if($z==$num_options) {
//$z=$num_options.'+'; // not sure whether this is going to protest..
											}
$HowManyYrs['$z'] = $z;
 }

echo "<pre>";
print_r($z);
echo "</pre>"; 

echo "<pre>";
print_r($HowManyYrs);
echo "</pre>"; 

and now here is the results...

8

Array
(
[] =>

[$z] => 7
)

What am I missing here?

Thanks LB,
Don

[laserlight]

I suggest handling the last element separately:

// For the header / include:
$num_options = 7;

// initialize array, with empty start option:
$HowManyYrs = array("" => " ")

for ($i = 1; $i < $num_options; ++$i)
{
    $HowManyYrs["$i"] = "$i";
}

$HowManyYrs["$num_options+"] = "$num_options+";

echo "<pre>";
print_r($z);
echo "</pre>";

The problem with leatherback's example is that '$z' is a literal string '$z', not a string whose contents is that of the variable $z.

[dmacman1962]

Thanks laserlight, your suggestion worked great. (thanks to you to leatherback).

I changed 2 things...

1)

 $HowManyYrs = array("" => " ");

2)

 print_r($HowManyYrs);

...and this gave me the array I needed for my function.

Thanks to both of you!

Don

[laserlight]

Oops, sorry about that. I should have checked for typographical errors.