[RESOLVED] how to start a session when a button is clicked and destroy when another bttn clicked

mars16

i need a very simplified log-in / logout process for learning purposes.

a code to start me off is very much appecaited.

1)when a log-in button is clicked i want a session to start. similarly when another button is clicked i want the session to be destroyed. this should apply acoss the whole site and not just for one particular page.

2) to know that a session is on, i want an if statement that evalutes if a seession exsist. If so, a text saying "session exsist" to show up.

i read on this alot but still confused.

leatherback

if((array_key_exists('authorisatie', $_SESSION)) && ($_SESSION['authorisatie']==1))
    {
    $loggedin = 1;
    $this_user = $_SESSION['user_extra'];
    }
else
  {
  $loggedin = 0 ;
  include("Login details");
  }

if(isset($_GET['logout']))
  {
  session_destroy();
  $loggedin=0;
  }

if(loggedin)
  {
  // do stuff
  }

mars16

which page is this code suppose to go in?

please bear in mind the buttons for log-in and log-out am using are graphics and not a form submit button.

please cooment where something is not obvious.

mars16

which page is this code suppose to go in?

please bear in mind the buttons for log-in and log-out am using are graphics and not a form submit button.

please cooment where something is not obvious.

jignesh1

if i would u create a config.php and put in the header.php that way it would recoginze and display the button login or logout button

mars16

jignesh1 , i don't understand what you mean.

jignesh1

let say u have forum like phpbuilder
when u r not logged in u see a txt input for username and password
and when u r logged in u see ur name and logout button

this thing are included in header file which are display in all the page of website
and config.php is something that going to make sure the user is logged in or not

mars16

jignesh1, am lost so please bear with me. You have mentioned 2 pages, config.php and header.php.

Now, from the code thats been pasted on this thread, which part of it i paste in config.php and which part of it i paste in header.

For now tell me exactly what to do i will try understand what is going on later because i can't make any sense of it now without seening the code working.

Rememeber, i don't want any username or password, just a simple "log-in" graphic to start a session, and a log-out graphic to destroy session. And an if statament to evelaute if session exsist, which i believe is the code above, just don't know what to do with it, i.e. which page.

leatherback

Hi Marsh,

What I gave you was a set of commands that can help you to evaluate whether a session is present, and an example to see whether the person is logged in. Not a ful working user-namagement system.

As I do not know how you store whether or not a user is logged in, it is impossible for me to give you a working solution. This is also true for the question 'where do I put this code'. You need to decide that. The login script (ll the way to the question "Is the user logged in", you should save as a separate file, e.g., with your settings.inc, and include it on every page. The rest of the script snippet you can use on each page, to determine which action to take.

I'll explain the script a little for you, to get you going:

// Let us start a session:
session_start();

// Lets see whether a variable called authorisation was passed 
// in the session from the previous page. 
// We require a value of one of that variable for it to be valid
if((array_key_exists('authorisation', $_SESSION)) && ($_SESSION['authorisatie']==1))
    {
    // Nice, the variable was set with the right value: The user must be logged in.
    $loggedin = 1;
    // Some more info (e.g., the user ID) is stored in he user_extra variable in the session.
    $this_user = $_SESSION['user_extra'];
    // Now set a variable with the link to logout:
    $loglink = "<a href=\"".$_SERVER['SCRIPT_NAME']."?logout=1\"><img src=\"image.png\"></a>";
    }
else
  {
  // OK, the authorisation was not set, or not equal to one: The person is not logged in.
  $loggedin = 0 ;
  // Create a link for the menu, to a login system
  $loglink = "<a href=\"".$_SERVER['SCRIPT_NAME']."?login=1\"><img src=\"image.png\"></a>";
  }

// Did the user ask to be logged out?
if(isset($_GET['logout']))
  {
  // Then destroy the session, and set loggedin to 0.
  session_destroy();
  $loggedin=0;  

  // Do not forget to modify the link to a login system
  $loglink = "<a href=\"".$_SERVER['SCRIPT_NAME']."?login=1\"><img src=\"image.png\"></a>";
  }

// Did the user ask to login?
if(isset($_GET['login']))
  {
  // Include your login script
  include("Login details");
  }

// Is the user loggen in?
if(loggedin)
  {
  // do stuff
  } 
else  // no he was not
  {
  do other stuff
  }

mars16

i have tried to understand the above but i couldn't but never mind i can do what i want now.

The following is a simple code am using (in case any total begginer would benefit from it), which is all i wanted at this stage.

a start session and close session without username password entry (so don't use it if its for real project, am just practicing techniques) and change the menu to login or log out depending on session existance.

script to check session, if there is none then set session, or if there is sesion hend destroy.

<?PHP
// Let us start a session:
session_start();

//if there is no session, mean user clicked on login button so set a session and return them to home
if (!isset($SESSION['loggedin'])) {
$SESSION['loggedin']="loggedin";
header('Refresh: 3; URL=home.php');
print("You are now LOGGED IN. You will be redirected.");
}

//else i assume user must have clicked on logout so destroy session
else {
//remove all the variables in the session
session_unset();

// destroy the session
session_destroy();

//header( 'Location: destin.php') ;
header('Refresh: 3; URL=home.php');

print("You are now LOGGED OUT. You will be redirected.");
}

for the menu, if statement to show "log in" or "log out" depending on the above code.

<?php
if (!isset($_SESSION['loggedin'])) {
print ("<a href='loginout.php'>LOG IN</a>");
}
else {
print ("<a href='loginout.php'>LOG OUT</a>");
}
?>