Displaying Month Name

Louis-Platt

$formatdate = explode("-", $match->date);
$month = $formatdate[1];
$year = $formatdate[0];
$day = $formatdate[2];


if ($month != $prev_month) {

echo "<tr><th colspan=7 align=center>";
echo date("M-d-Y", mktime(0, 0, 0, $day, $month, $year));
[B]echo $month." ".$year;[/B]
echo "</th></tr>\n";
} // end if

I would like to display the month as the month name and year, for example "March 2007", it currently appears as "03 2007", I have tried various functions and I am getting nowhere with it, I have tried strtotime, mktime, date but all seem to return errors. Please can you help?

firemankurt

<?php
list($year,$month,$day)= explode("-", '2006-12-28');

if ($month != $prev_month) {

echo "<tr><th colspan=7 align=center>";
$DisplayDate = date("M Y", mktime(0, 0, 0, $day, $month, $year));
echo $DisplayDate;
//echo $month." ".$year;
echo "</th></tr>\n";
} // end if 
?>

aspekt9

<?php
echo date("F Y");
?>

firemankurt

Hey aspekt9,

Doesn't

<?php
$month = date('m');
$day = date('j');
$year = date('Y');
echo date("F d, Y", mktime(0, 0, 0, $month, $day, $year));
?>

eqate to:

<?php
echo date("F d, Y");
?>

And output "March 03 2007" not "March 2007"
??????

firemankurt

Louis,
in

$formatdate = explode("-", $match->date);

are you trying to get todays date like

$formatdate = date("Y-d-m");