Help with readdir script

[kbc1]

Hi

I am working on a little script that reads the contents of a folder that the script itself is placed within.

My question is now this. I need the script to be able to detect if the files read are in fact files or folders and depending on the result, change the target of the hyperlink to open in a new window for files (_blank) and the parent window itself for folders.

Here is my code:

	$path  =  ".";  

$dir_handle  =  @opendir($path)  or  die("Unable to open $path");  
while  (false !== ($file = readdir($dir_handle)))  {  
	if ($file == "." || $file == ".." || $file == "index.php")
	continue;

	$ext = strrchr($file, '.');   

	if ($ext == ".pdf") {
		$icon = "/images/adobe.jpg";		
		$type = "Adobe Acrobat PDF";
	} elseif ($ext == ".doc") {
		$icon = "/images/word.jpg";		
		$type = "Microsoft Word";
	} elseif ($ext == ".xls") {
		$icon = "/images/excel.jpg";		
		$type = "Microsoft Excel";
	} else {
		$icon = "/images/office.jpg";		
		$type = "Microsoft Office";
	}



	echo  "<img src=\"$icon\" alt=\"$type\" title=\"$type\" width\"18\" height=\"18\">
		   <a href=\"$file\" title=\"Click to download $file\" target=\"_blank\">$file</a><br />";  

}  

closedir($dir_handle);

Any help will be appraciated
Thanks in advance

[timus]

Hey

would using is_dir() be of any use?

returns a bool value

Regards

Tim

[kbc1]

Hi Tim

Yes it would be but its where i use the is_dir function in the code snippet that would be helpful if you could point out?

If i knew that i could also change the icon to represent a folder which would be very useful.

Many thanks

[Weedpacket]

Think about it logically for a minute (y'know, like a programmer would).
You have to use it before you make the decision about which icon to use.

It has to make this decision by looking at the value of $file.

You probably don't want to waste its time with things like "." and "..".

You have to do one thing if it returns true, and something else if it returns false.
(PHP has a syntax construct for this).

If it returns true, meaning that $file is a directory, you want to return (oh all right, output) a "folder" icon.

Otherwise ("else") you want to output an icon depending on what the file extension is.