convert code to php4

[TravisB]

I found some sample code I would like to use but it said I might need to change it for php4. I ran it and sure enough it does not work. What would I need to change for this to work?

<?
class SortableExample {
	protected $conn;
	protected $user = 'test';
	protected $pass = 'test';
	protected $dbname = 'scriptaculous';
	protected $host = 'localhost';
	public function __construct() {
		$this->conn = mysql_connect($this->host, $this->user, $this->pass);
		mysql_select_db($this->dbname,$this->conn);
	}
	public function getList() {
		$sql = "SELECT * FROM categories ORDER BY orderid";
		$recordSet = mysql_query($sql,$this->conn);
		$results = array();
		while($row = mysql_fetch_assoc($recordSet)) {
			$results[] = $row;
		}
		return $results;
	}
	public function updateList($orderArray) {
		$orderid = 1;
		foreach($orderArray as $catid) {
			$catid = (int) $catid;
			$sql = "UPDATE categories SET orderid={$orderid} WHERE catid={$catid}";
			$recordSet = mysql_query($sql,$this->conn);
			$orderid++;
		}
	}
}
?>

Thanks,
Travis

[Azala]

Something like this:

<?
class SortableExample {
    var $conn;
    var $user = 'test';
    var $pass = 'test';
    var $dbname = 'scriptaculous';
    var $host = 'localhost';

function __construct() {
        $this->conn = mysql_connect($this->host, $this->user, $this->pass);
        mysql_select_db($this->dbname,$this->conn);
    }

function getList() {
        $sql = "SELECT * FROM categories ORDER BY orderid";
        $recordSet = mysql_query($sql,$this->conn);
        $results = array();
        while($row = mysql_fetch_assoc($recordSet)) {
            $results[] = $row;
        }
        return $results;
    }

function updateList($orderArray) {
        $orderid = 1;
        foreach($orderArray as $catid) {
            $catid = (int) $catid;
            $sql = "UPDATE categories SET orderid={$orderid} WHERE catid={$catid}";
            $recordSet = mysql_query($sql,$this->conn);
            $orderid++;
        }
    }
}
?> 

Note that you must manually call __construct as this is not automatically done in PHP4.

So in PHP5 you would do:
$mySortable = new SortableExample();

in PHP4:
$mySortable = new SortableExample();
$mySortable->__construct();

Optionally you can change the __construct name to your classname to achieve the same "effect" as in PHP5.

function __construct becomes function SortableExample

[Roger_Ramjet]

Better yet, change the name of the constructor to the same as the class:
"A function becomes a constructor, when it has the same name as the class. If a class has no constructor, the constructor of the base class will be called, if it exists."

So just change function __construct to function SortableExample

Sorry Azala, did not see you had already said that. :o