condition where 2 vars aren't set

djbryson

So... a condition where 1 var isn't set:
if (!$var)
{
whatver;
}

but what if you want a condition where 2 vars aren't set.
I've tried the following without success

if ((!$var1) && (!$var2)) {

if (!$var1) || (!$var2) {

If !($var1 || $var2) {

lil help...

Piranha

If you want to know if the variables are set or not you should use [man]isset[/man]. If you mean that none of the variables should be set to go into the if-statement it should be something like this:

if (!isset($var1) && !isset($var2)) // None of the variables can be set if this should be true.
    echo "none of the variables were set";
elseif (!isset($var1) || !isset($var2)) // At least one of the variables is not set to make this true.
    echo "one of the variables were set"; // Since the first if-statement looked at both variables we can be sure to say that one of them are set at this stage.
else
    echo "both variables were set";

djbryson

well, i don't know if I need isset or not.... i just want to know if they're blank or not. if (!$var) works fine for me. Not sure what the diff is.
So i guess it would be
if (!($var1) && !($var2)) {

leatherback

Did you read the post by piranha?

// are they set?

if(! isset($var1) && !isset($var2))
  {
  // do stuff
  }

// are they blank?
if(($var1 == "") && ($var2==""))
  {
  // do stuff
  }

madwormer2

What about

if(!isset($var1,$var2)) { 
// At least one's not set
}

One function, could it really be that easy 😮

Edit: apparently not lol. Ignore me

NogDog

The specifics ultimately depend on upon what you mean by a variable being "set", "blank", etc. If you mean the value is an empty string or nothing but white-space, then probably the most thorough expression (i.e.: won't possibly throw notice-level errors if either variable is not set at all) would be:

if((!isset($var1) or (trim($var1) === "")) and (!isset($var2) or (trim($var2) === "")))
{
  // neither variable is "set"
}