[RESOLVED] Using isset() With an Image Submit Button

[scriderpsd]

I'm trying to check to see if the user has clicked the submit button on a form. In this case the submit button is not the standard grey HTML button but an image.

if (isset($_POST['submit_absence'])) {
				mysql_query($sqlInsert,$conn) or die('Error, query failed');	
}

submit_absence is the name of the submit image.

echo '<input type="image" name="submit_absence" src="images/submit.JPG"></input>';

If I use the above code, nothing is ever set and the query never executes.

if I use..

echo '<input type="submit" name="submit_absence" value="Submit Request"></input>';

...then it gets set and the query executes. I need to be able to use the image rather than the lame HTML submit button.

Any help??

Thanks,

Scott

[Piranha]

Use a hidden value instead, then it will work.

[scriderpsd]

Hey Piranha, are you saying to change the input type of the submit button to hidden rather than image? Or, are you saying to add another form element with type=hidden???

[leatherback]

You add a hidden form element to the form.

This is in general better practice, as the button value does not have to be passed by the form, and is dependent on the browser