paramater passing by include

cmp241

Hello everyone,

I have two files a.php and b.php. I need to pass parameters from a.php to b.php. So, I attempted to use an include statement, but it doesn't work. here's a thread that discuss the problem, but I still can't get it to work for me.

http://phpbuilder.com/board/showthread.php?t=10335506&highlight=include

a.php

<?php 
$dname = "music";
$tname = "genre";

include 'http://localhost/default/a.php?id=$dname&dv=$tname&tv=all'; ?>

b.php

<?php
$dname = $_GET['id'];
$tname = $_GET['dv'];
$fname = $_GET['tv'];

?>

Now I don't want to change b.php because I pass parameters to it like this

<p align="center"><a href="http://localhost/default/b.php?id=<?php echo $dname?>&amp;dv=<?php echo $tname?>&amp;tv=all">Show All record(s)</a></p>

So how can I pass these paramaters from a.php to b.php and I don't want to use a form and use hidden fields or anything like that. I don't want any user interaction, it should just see the include statement, take the variables and pass it to the next script.

Thanks,

CMP241

devinemke

[man]include[/man]d files inheirit the variable scope of the parent file. therefore you do not need to pass them via GET.

a.php

<?php
$var = 'this is a string';
include('b.php');
?>

b.php

<?php
echo $var; // outputs "this is a string"
?>

cmp241

Thanks for your prompt reply devinemke. I tried what you suggested and it worked. However, let's say we have the same files.

a.php

<?php

$dname = "music";
$tname = "genre";
include 'b.php'; 

?>

b.php

<?php

$dname = $_GET['id'];
$tname = $_GET['dv'];
$fname = $_GET['tv'];

?>

let's add another file, c.php

<p align="center"><a href="http://localhost/default/b.php?id=<?php echo $dname?>
&amp;dv=<?php echo $tname?>&amp;tv=all">Show All record(s)</a></p>

now, we have both files a.php and c.php trying to access b.php. Now the only possible way I can see b.php serving both a.php and c.php is by having some kind of control bit which does something like this in file b.php.

<?php
if($c == 2)
{
//do nothing this deals with a.php
}
else
{//this deals with c.php
$dname = $_GET['id'];
$tname = $_GET['dv'];
$fname = $_GET['tv'];
}
?>

and change file a.php and add a c variable like this:
a.php

<?php

$dname = "music";
$tname = "genre";
$c = 2;
include 'b.php'; 

?>

Is this the only option?

Thanks

laserlight

Um, why can you not include 'b.php' in c.php?

NogDog

What you might want to consider doing is defining a function in your include file, which you then call with the requisite parameters in the main script:

b.php (include file):

<?php
function func_b($id, $dv, $tv);
{
  // do whatever needs to be done with $id, $dv, and $tv
}
?>

a.php:

<?php
require_once 'b.php';
func_b($dname, $tname, 'all');
?>

cmp241

NogDog, I tried what you suggested and it works as good as the include, but it still doesn't take into consideration the values that c.php is passing, so when I try to access b.php via c.php it doesn't work because I didn't set the function in b.php to handle c.php. so I am concluded that the only way to work around pleasing both scripts is to have a control bit as I posted earlier. Please tell me any suggestions.

laserlight, c.php have a series of hyperlinks which is implemented via a loop

<?php
....
while ($i < mysql_num_fields($result)) {
   $meta = mysql_fetch_field($result, $i);
   if (!$meta) {
       echo "No information available<br />\n";
   }
   ?>
  <TH bgcolor="#FFFFFF"><a href="http://localhost/default/b.php?id=<?php echo $dname?>&amp;dv=<?php echo $tname?>&amp;tv=<?php echo $meta->name?>"> <?PHP echo $meta->name; ?></a></TH>
<?php
   $i++;
}
mysql_free_result($result);
mysql_close($con);
?>

so the user chooses which link and that's how the variables content to be passed to b.php is set. So, I really don't see how I can just place an include statement here, any suggestions will be appreciated

Thanks to All.

laserlight

Ah, so the user selects a link... and the link is to b.php. Since you already pass the value on the query string to b.php, what is the problem?

Put it another way: what is the purpose of these files? Which files do you expect the user to visit, and which are purely meant to be included?

leatherback

Hi,

I am not sure what 'a', 'b' and 'c' do, besides playing with variables. I presume they have other code as well, and b.php is just a set of functions to say retrieve data from the database, and produce some output. If so.. treat it as an include file, and not as a stand-alone file. So you add a file called d.php to your system, which basically only handles the variable input from c.php for b.php:

$dname = $_GET['id'];
$tname = $_GET['dv'];
$fname = $_GET['tv']; 
include("b.php" );

In a.php you include b.php:

// blablabla

$dname = "music";
$tname = "genre";
include 'b.php';

// blablabla

in d you include b.php

// blablabla
$dname = $_GET['id'];
$tname = $_GET['dv'];
$fname = $_GET['tv']; 
include("b.php" );
//blablabla

In c you link to d.php, instead of b.php

cmp241

laserlight, the problem is I have two files (a.php and c.php) trying to access b.php. file c.php is based on the user interaction, while file a.php is just suppose
to execute some code and pass the info along to file b.php. Since c.php variables are dynamic and are passed by a url such as

<a href="http://localhost/default/b.php?id=<?php echo $dname?>
&amp;dv=<?php echo $tname?>&amp;tv=<?php echo $meta->name?>

and by the way what's being passed is not a variable (id, dv, tv (i don't know what you call them)) and in a.php variable are static and are passed by a variable.
So now when both try to access the file there needs to be some control in b.php
to handle both files(a.php and c.php). Really there's no problem, I already stated a solution
above and I just wanted to know if theres a better solution, but it seems that everyone is point me to the same direction.

Leatherback, you are basically saying this:
a.php d.php<-- c.php

\ /
b.php

Now I don't see how this is a better solution, I think my solution is the best just have some control in the b.php, which handles both a.php and c.php.

Thanks to everyone for your help and insight.

The question was asked,

what is the purpose of these files?

a.php = showfield.php, which is a file that shows a database, a table, and field name, then the user have the option to choose to show the records for a
specific field or show the record of all fields by clicking on the appropriate hyperlink which leads to b.php.

b.php=showrecord.php, this file shows all info from a database, table, fields, and records.

c.php = createdatabase.php, this file creates a new database with a table and number of fields specify by the user and then after if creates all this, I put the include statement to file b.php, so that I can print what I just created.

I would post my code but I was trying to following the methodology of KISS (keep it simple, you know the rest).

Thanks to all for your help