Dear friends,
Im just a kid out to learn PHP and MYSQL, but im having problems when searching my little MySQL database using php. PLEASE HELP MEEEE:o
I did a search under "gulaid" on the employee table, the search was successfull only thing is it doesnt allow you to view the actual results.. I can see that PHP has searched the database and the result count of "3" is correct three employees named "gulaid" do exist only thing is that the page doesnt include the actual data:
here is the displayed HTML:
<head>
<title>
</title>
</head>
<body>
<form name="form" action="search.php" method="get">
<input type="text" name="q" />
<input type="submit" name="Submit" value="Search" />
</form>
<p>You searched for: "gulaid"</p>Results1.) <br /> <a href="?s=1&q=gulaid">Next 10 >></a><p>Showing results 1 to 1 of 3</p>
</body>
------------------------------------------------------
The PHP code used is below:
<html>
<head>
<title>
</title>
</head>
<body>
<form name="form" action="search.php" method="get">
<input type="text" name="q" />
<input type="submit" name="Submit" value="Search" />
</form>
<?php
// Get the search variable from URL
$var = @$_GET['q'] ;
$trimmed = trim($var); //trim whitespace from the stored variable
// rows to return
$limit=1;
// check for an empty string and display a message.
if ($trimmed == "")
{
echo "<p>Please enter a search...</p>";
exit;
}
// check for a search parameter
if (!isset($var))
{
echo "<p>We dont seem to have a search parameter!</p>";
exit;
}
//connect to your database ** EDIT REQUIRED HERE **
mysql_connect("localhost","user","pass"); //(host, username, password)
//specify database ** EDIT REQUIRED HERE **
mysql_select_db("corporate") or die("Unable to select database"); //select which database we're using
// Build SQL Query
$query = "select * from employee where LastName like \"%$trimmed%\"
order by LastName"; // EDIT HERE and specify your table and field names for the SQL query
$numresults=mysql_query($query);
$numrows=mysql_num_rows($numresults);
// If we have no results, offer a google search as an alternative
if ($numrows == 0)
{
echo "<h4>Results</h4>";
echo "<p>Sorry, your search: "" . $trimmed . "" returned zero results</p>";
// google
echo "<p><a href=\"http://www.google.com/search?q="
. $trimmed . "\" target=\"_blank\" title=\"Look up
" . $trimmed . " on Google\">Click here</a> to try the
search on google</p>";
}
// next determine if s has been passed to script, if not use 0
if (empty($s)) {
$s=0;
}
// get results
$query .= " limit $s,$limit";
$result = mysql_query($query) or die("Couldn't execute query");
// display what the person searched for
echo "<p>You searched for: "" . $var . ""</p>";
// begin to show results set
echo "Results";
$count = 1 + $s ;
// now you can display the results returned
while ($row= mysql_fetch_array($result)) {
$title = $row["1st_field"];
echo "$count.) $title" ;
$count++ ;
}
$currPage = (($s/$limit) + 1);
//break before paging
echo "<br />";
// next we need to do the links to other results
if ($s>=1) { // bypass PREV link if s is 0
$prevs=($s-$limit);
print " <a href=\"$PHP_SELF?s=$prevs&q=$var\"><<
Prev 10</a>  ";
}
// calculate number of pages needing links
$pages=intval($numrows/$limit);
// $pages now contains int of pages needed unless there is a remainder from division
if ($numrows%$limit) {
// has remainder so add one page
$pages++;
}
// check to see if last page
if (!((($s+$limit)/$limit)==$pages) && $pages!=1) {
// not last page so give NEXT link
$news=$s+$limit;
echo " <a href=\"$PHP_SELF?s=$news&q=$var\">Next 10 >></a>";
}
$a = $s + ($limit) ;
if ($a > $numrows) { $a = $numrows ; }
$b = $s + 1 ;
echo "<p>Showing results $b to $a of $numrows</p>";
?>
</body>
</html>
