[RESOLVED] help with passthru

[snade]

I am writing a php application which processes information from a database, then calls another php script to graph it. All output is displayed in a web page. I can't get any output from the called application to display using passthru(), exec() or popen().
I have tried specifying a full path as well as filename only. Both applications work fine by themselves.

i.e.

first.php

<?php

echo "hi";
echo "<br>";
passthru('second.php');
?>

second.php

<?php

echo "here I am";
?>

executing first.php displays "hi" only.
executing second.php displays "here I am."

Thanks for any suggestions.

[banzaimonkey]

Why not just use include()?

I think the other functions are intended for non-PHP use. (I.e. command-line operations for programs other than PHP.)

[HalfaBee]

Yep, passthru() will pass the non parsed code to the browser.
the <? ?> will hide it from the webpage. A view source would have shown this.

[snade]

thanks,

that might just work, but the second script is a program which generates a .png image, so it's a little more complicated than my example. I have to do some re-coding, but I'll give that a shot.

[HalfaBee]

You need to put an <img > tag in to reference the png the script creeates and saves to your webspace.

[snade]

Thanks. I should have thought of that. It works - much easier than rewriting.

[bradgrafelman]

Don't forget to mark this thread resolved.