[RESOLVED] Removing the submit value

[Neko_D]

I could not think of a better subject. I have a script that reads and writes from a cookie. The problem is that whenever I build the cookie I am always getting the value of the submit button in my output. When, I believe, I should be getting no output at all when I do not send any values.

Code:

<?php
       if($_POST["sub"])
       {
            $label;
            $out;
            $td;
                 $label = "<div>Cookie Contains</div>";

             foreach($_COOKIE as $key => $item)
             {
                  $out .= "<div>$key = $item</div>";
                  setcookie($key, "", time()-600, "/");
             }//end foreach

             foreach($_POST as $key => $label)
             {
                  if($key == "sub") {}
                  else
                  {
                       $td = "<div>$key : $lab</div>";
                       setcookie($key, $label, time()+(7200), "/");
                  }
             }//end foreach
   }//end if
?>

Thanks

[scross]

ok, your problem stems from lots of variable misnaming in your second foreach loop:

foreach($_POST as $key => $label)

Change "$label" to "$value" (or something else which is not used)

Change:

if($key == "sub"){}
else
{

to:

if($key != "sub"){

Which has exactly the same meaning, it's just a lot simpler. Change:

$td = "<div>$key : $lab</div>";

to:

$out .= "<div>$key : $value</div>";

And also change:

setcookie($key, $label, time()+(7200), "/");

to:

setcookie($key, $value, time()+7200, "/");

Then finally you'll need to change:

$label = "<div>Cookie Contains</div>";

to:

$out = "<div>Cookie Contains</div>";

And all your output will be stored in a variable called $out at the end. Oh and you can also remove:

$label;
$out;
$td;

because these lines have absolutely no effect.