Get user from [QUOTE user=USERNAME]

middleman666

hey people,

I have:

[QUOTE user=USERNAME]

and I want to get the USERNAME from it.
I've been searching for an easy solution to this and I've been pushed towards using preg_match, but I don't understand how the patterns are made.

Can someone shove me in the direction of a decent tutorial on how to write the pattern for this?

or if your feeling kind and have the pattern at hand... ?

Thanks.

middleman666

ok, so far I've got:

$bbcode_regex = "/\[QUOTE user\=(.+?)](.+?)\[\/QUOTE\]/s";
$bbcode_replace = '<span class="Fquote">Previously, $1 said:<br /> "$2"</span>';
$replytext = preg_replace($bbcode_regex, $bbcode_replace, $replytext);

which works fine on the first quote, but how do I get it to work with quotes within quotes?

i.e.

[QUOTE user=USERNAME] 

this is quote one

[QUOTE user=USERNAME] 

this is quote two

[/QUOTE]

[/QUOTE]

middleman666

right... I now have:


$quotes = 3;

$i = 0;
for($i = 1; $i < $quotes; $i++) { 
  $bbcode_regex = '/\[QUOTE user\=(.+?)](.+?)\[\/QUOTE\]/s';
  $bbcode_replace = '<span class="Fquote">Previously, $1 said:<br /> $2</span>';
  $replytext = preg_replace($bbcode_regex, $bbcode_replace, $replytext);
}

So I'm thinking I need a way of counting all the [/QUOTE]'s from the string so I can use this number as $quotes + 1.

Anyone know a string count function?

Thanks.

EDIT:

new problem, I can't actualy do anything with the user i.e. $1... I want to do something like this:

$DNresult = mysql_query("select displayname from Profile where username = $1 limit 1");
$DNrow= mysql_fetch_array($DNresult);
$1 = $DNrow['displayname'];

this just returns warnings because of the $1, is there any way of turning $1 into a proper/usable variable?

Thanks.