add variable to variable name

[themanwhowas]

i dont like being held by the hand through this type of thing but i really cant remember how i did it before.

Following my previous post i now have this

$numbers = range(1,20);
shuffle($numbers);
$randno = array_slice($numbers, 0, 5);

to get my 5 random numbers.

i need these numbers appended to the end of a variable. eg.

$randno['3'] == 4 so i want $yemen4,
$randno['0'] == 11 so i want $yemen11
at the end i should have 5 random $yemens

$yemen1 = 'blah blah blah';
$yemen2 = 'blah blah';
$yemen3 = 'blah';
etc

now i would like all of the random yemens echo'd so i guess they should be in an array.

I have been racking my brains and i cant work out how to do this. please someone help
i could use

foreach($randno as $val)
{
if ($val == 1)
{
echo 'blah blah';
}
if($val == 2)
{
echo 'blah';
}
echo '<br />';
}

but im sure there is a more efficient way. Sorry for imposing babysitting duties upon thee

[NogDog]

The best(?) way would be to use an array:

$yemen[1] = "blah blah blah";
$yemen[2] = "blah blah";
$yemen[3] = "blah";
echo $yemen[$randno[0]];

[Protato]

As NogDog pointed out, array's are probably the best way to handle this. To explicitly answer the question "add variable to variable name" though;

$i = 3;
//var name
$var_name = 'var'.$i;

//create a var name $var3.
$$var_name = 'blah blah blah';

//both are the same
echo $$var_name."<br>";
echo $var3."<br>";

[NogDog]

And another option, using "complex variable notation":

$yemen1 = "blah blah blah";
$yemen2 = "blah blah";
$yemen3 = "blah";
$numbers = range(1,3);
shuffle($numbers);
foreach($numbers as $randNo)
{
   echo "<pre>".${'yemen'.$randNo}."</pre>\n";
}

🙂