functions in php5 not like php4?

[pinkcow]

hi

why does the function overwrite $db? in php4 the parameter is copied and not passed by reference.

function renderNews($db, $tbl, $path, $freetag, $markUp) {
		$db->q("select txt from ".$tbl['cat']." where ".substr($query,0,-4));
		while($db->nr())
			$cat .= $db->r['txt'].' / ';

	$tmp .=		substr($cat,0,-2).'</td>';

            return $tmp;
}

$db->q($query);
while($db->nr()) {	
		echo renderNews($db, $tbl, $path, $freetag, $markUp);

	$i++;
}

[NogDog]

Yes, I believe this is a difference in the way PHP 5 handles object references versus copies now. As per http://www.php.net/manual/en/language.oop5.basic.php:

When assigning an already created instance of a class to a new variable, the new variable will access the same instance as the object that was assigned. This behaviour is the same when passing instances to a function. A copy of an already created object can be made by cloning it.