[RESOLVED] Help with syntaz on variable variable

davidjames52

Hi all,

Could some one please help me with syntax on a variable variable please. I need to pull a value from a predefined array while in a loop. Here is my variable variable.

$playera = $playerarray{'$loops'}[$a];

I need it to end like this.

$playera = $playerarray1[0];

$loops is the loop variable and $a is a predeifned variable set from 0-64. I know it will something silly that I am doing wrong but first time using variable variables.

Thanks Heaps.

Jramz

davidjames52 wrote:
Hi all,

Could some one please help me with syntax on a variable variable please. I need to pull a value from a predefined array while in a loop. Here is my variable variable.

$playera = $playerarray{'$loops'}[$a];

I need it to end like this.

$playera = $playerarray1[0];

$loops is the loop variable and $a is a predeifned variable set from 0-64. I know it will something silly that I am doing wrong but first time using variable variables.

Thanks Heaps.

try something like this: (ignore this, i was way off base with that one)


$playera = $playerarray$loops[$a];

i'm not sure cause i just ran a quick test of it on my server, but it looks to work

~Jeremy


[COLOR="SeaGreen"]try something like this: (this one is tested and works!)[/COLOR]
[code=php]

$temp = "playerarray$loops"
$playera = $$temp[$a];

that looks right

davidjames52

I get a parse error with that of some sort as nothing comes up on the screen. I take that statement outand all works ok.

Jramz

davidjames52 wrote:
I get a parse error with that of some sort as nothing comes up on the screen. I take that statement outand all works ok.

Yes using the first example you'll get a parse error, use the second example:

try something like this: (this one is tested and works!)

$temp = "playerarray$loops" 
$playera = $$temp[$a];

that looks right

NogDog

While the variable variable thing will work, the real question to ask here is whether or not you could be using a 2-dimensional array, instead.

bradgrafelman

Although you could correct your code like so:

$playera = ${'playerarray'.$loops}[$a];

NogDog is indeed correct in questioning the application of variable variables here; wouldn't arrays make more sense?

Jramz

bradgrafelman wrote:
Although you could correct your code like so:
$playera = ${'playerarray'.$loops}[$a];
NogDog is indeed correct in questioning the application of variable variables here; wouldn't arrays make more sense?

Indeed a wonderful question, but as i eluded to here, not everyone wants to do things the easy way...

😉

~Jeremy

davidjames52

Thanks heaps E1 I ended up using Jramz example and that worked perfectly

As for the arrays issue I am using loops to echo out the results of 6 different arrays which must be kept seperate so there for the variable variable issue.

HAG1