[RESOLVED] Regex help

[big_nerd]

Hello all,

I am in need of some regex help. I am still trying to grasp exactly how it works.

I need to search a string (often large) for a markup, such as

<graph type="1" id="12345">

With that, I need to erase it (as it is invalid markup) and get the values.

I will be using this to grab info from a database, based on the values provided.

I would then insert text based on that (an <img ) in order to display the graph.

Thanks in advance,

[bradgrafelman]

Well, if you specifically wanted to match that type of string, you might do:

preg_match_all('/<graph\s+type=["\'](.*)["\']\s+id=["\'](.*)["\']\s*>/iU', $string, $matches);

Now, the only problem with that is that using a different order of parameters (e.g. <graph id="12345" type="1">) won't be matched.

[big_nerd]

brad,

Thank you AGAIN...

The information is coming from an excel file which I am saving into a database. Not my idea, but that's what they want.

When it spits it out, it will provide the user with the code.

I tried it out, but I am unsure if I am doing something wrong:

function setgraph($str) {
	preg_match_all('/<graph\s+type=["\'](.*)["\']\s+id=["\'](.*)["\']\s+>/iU', $str, $matches); 
	var_dump($matches);
}

setgraph('What a nice Day <graph type="1" id="12345">');

And I am getting the following output:

array(3) { [0]=> array(0) { } [1]=> array(0) { } [2]=> array(0) { } } 

Any thoughts?

[bradgrafelman]

Ah, you grabbed a copy of my code before I could update it. If you'll notice, my post now has a '*' after the last \s instead of a '+'.

[big_nerd]

bradgrafelman,

Thank you once again, I can't say enough how great you all are.

big.nerd