[RESOLVED] More than 1 conditional in a function

[Tim_Silva]

This is a great function I use to echo timestamps as "how long ago" timeframe. This function rounds up the time to the smallest hour, so that 2:55 echos "2 hours ago". The only conditional in this function is

if($difference != 1) $periods[$j].= "s";

and what it does is to add an "s" if the second, minute, hour... is not 1 (pluralization).

I need now to add another conditional so that for anytime greater than 5 hours and less than 24 hours it will echo just the word "Today". I tried many possibilities without much success.

 function ago($timestamp){
    $difference = time() - $timestamp;
    $periods = array("second", "minute", "hour", "day", "week", "month", "years", "decade");
    $lengths = array("60","60","24","7","4.35","12","10");
    for($j = 0; $difference >= $lengths[$j]; $j++)
      $difference /= $lengths[$j];
    $difference = round($difference);
    if($difference != 1) $periods[$j].= "s";
    $text = "$difference $periods[$j] ago";
    return $text;
  }

Thanks for any help.

Tim

[dagon]

function ago($timestamp){
    $difference = time() - $timestamp;
	 if ($difference >=(5 * 60 * 60) && $difference<=(24 * 60 * 60) ) {
	 return ('Today');
	 }
    $periods = array("second", "minute", "hour", "day", "week", "month", "years", "decade");
    $lengths = array("60","60","24","7","4.35","12","10");
    for($j = 0; $difference >= $lengths[$j]; $j++)
      $difference /= $lengths[$j];
    $difference = round($difference);
    if($difference != 1) $periods[$j].= "s";
    $text = "$difference $periods[$j] ago";
    return $text;
  } 

i left the (5 60 60) in so you can see whats happening but you could just replace it with 18000

[Tim_Silva]

Dagon,

Your addition to the code was excellent. It did exactly what was supposed to do. Also, thanks for leaving the (5 60 60). That way, I was able to make changes and also see the logic behind it.

Thanks a lot.

Tim