Thanks for the suggestions. I know we are in the neighborhood with the 'special character' issues.

but neither of those worked. I was also looking for some clipper commands. Like go to the end of this string and chop off 1 character.

lot of remove carriage control code. (trim) But nothing yet that just says .... kill the last character.

Anyway the '&' is very special. grrrrrrr

kc

    You could extract just that section of the sting (the bit without '&limitsize=' in).
    Like so:

    $var = substr($var, 0, strlen($var) - strlen("&limitsize="));
    

    Try that, I haven't, lol.

      NogDog wrote:

      I copied and pasted your code, and it worked fine. Perhaps you are outputting the $sprint_user_photo_link variable instead of the $image_url that you save the replaced text in?

      Maybe it's different php code level. I think I have the displays right because I did everything but the '&' and get this output:

      Sprint user photo link after cleanup: http://pictures.sprintpcs.com//mmps/RECIPIENT/001_26xxx848d2ff0ca3_1/2.2?inviteToken=NEqrxxx5m8awcUcLo7qL& .

      I'll keep trying.

        What's happens if you only replace the "&" character ?

          If you are bothered, my code worked perfectly.

          $sprint_user_photo_link = 'http://pictures.sprintpcs.com//mmps/RECIPIENT/001_xxxxb848d2ff0ca3_1/2.2?inviteToken=NEqrxxJ5m8awcUcLo7qL&limitsize= ';
          $image_url = $var = substr(trim($sprint_user_photo_link), 0, strlen($sprint_user_photo_link) - strlen("&limitsize="));
          
          echo $image_url;
          // http://pictures.sprintpcs.com//mmps/RECIPIENT/001_xxxxb848d2ff0ca3_1/2.2?inviteToken=NEqrxxJ5m8awcUcLo7qL
          
            suntra wrote:

            What's happens if you only replace the "&" character ?

            code here:

            $image_url = str_replace('limitsize=', '', $sprint_user_photo_link);
            
            
            
            echo nl2br(".  \n Sprint user photo link after cleanup:  $image_url   ");
            
            
            
            
            
            
            $image_url = str_replace('&', '', $image_url);
            
            //   put in here <---           replace this, with this, in here
            
            echo nl2br(".  \n Sprint user photo link after cleanup #2 for '&':  $image_url   .");
            
            
            
            
            
            

            Output below: --------------------------------------------------------------------

            this is snatch Sprint photo link . Sprint photo link is (before clean) http://pictures.sprintpcs.com//mmps/RECIPIENT/001_266db848d2ff0ca3_1/2.2?inviteToken=NEqrJUJ5m8awcUcLo7qL&limitsize= .

            ..

            Sprint user photo link after cleanup: http://pictures.sprintpcs.com//mmps/RECIPIENT/001_266db848d2ff0ca3_1/2.2?inviteToken=NEqrJUJ5m8awcUcLo7qL& .

            Sprint user photo link after cleanup #2 for '&': http://pictures.sprintpcs.com//mmps/RECIPIENT/001_266db848d2ff0ca3_1/2.2?inviteToken=NEqrJUJ5m8awcUcLo7qLamp; .

              Like i said, mine works fine.

              Why mess around when you have something that works?

                rowanparker wrote:

                Like i said, mine works fine.

                Why mess around when you have something that works?

                Rowan, Thanks but
                It didn't work for me. Unless there's some other mistake I'm missing.

                $image_url = $var = substr(trim($sprint_user_photo_link), 0, strlen($sprint_user_photo_link) - strlen("&limitsize=")); 
                
                echo nl2br(".  \n Sprint user photo link after cleanup:  $image_url   ");

                output:

                Sprint user photo link after cleanup: http://pictures.sprintpcs.com//mmps/RECIPIENT/001_266db848d2ff0ca3_1/2.2?inviteToken=NEqrJUJ5m8awcUcLo7qL&

                This is approaching 'bug' territory. It found it and replaced it but ignored the '&'.

                In some doc I'm seeing (and it also show in my reply before this one) that '&' is sometimes represented by '&amp;'.

                Still researching.

                  Try:

                  $image_url = $var = substr(trim($sprint_user_photo_link), 0, strlen($sprint_user_photo_link) - strlen("&limitsize=") + 1);
                  
                  echo nl2br(".  \n Sprint user photo link after cleanup:  $image_url   ");[
                  

                  Should work, unless it just does not like your, lol.

                    kansaschuck wrote:

                    ...
                    In some doc I'm seeing (and it also show in my reply before this one) that '&' is sometimes represented by '&amp;'.

                    Still researching.

                    Are you doing a "view source" in your browser to see what is really there, as opposed to just what the browser itself is showing?

                    If it might be "&amp;", you could handle either/or with either of these:

                    $image_url = str_replace(array('&limitsize=', '&amp;limitsize=', '', $sprint_user_photo_link);
                    // ...or...
                    $image_url = preg_replace('/&(amp;)?limitsize=/', '', $sprint_user_photo_link);
                    
                      rowanparker wrote:

                      Like i said, mine works fine.

                      Why mess around when you have something that works?

                      this worked for me.

                      $image_url = str_replace('&amp;limitsize=', '', $sprint_user_photo_link);

                      whacha think?

                        Write a Reply...