Echoing Strings And Objects

IronTree

I have a header template where I have the usual meta and title tags. What I'm wanting to do is echo out an object in order for the title to be dynamic.

What does seem to work is if I echo out the $_GET ['string'] , however when I try something like echo $row->something; I get nothing. I'm assuming the object is not being read because it is in a different file?

Here are the files I have:

Header.php
page1.php
page2.php
Footer.php

What I do is include the header and footer in page1 and page2. Sorry if I'm rambling on. Any help would be appreciated.

NogDog

Tough to say without seeing any code. I'd suggest starting the debug process by making sure all errors are being displayed, so that you can see if the PHP parser has any useful info for you. Add the following to the top of the main script file:

<?php
ini_set('display_errors', 1);
error_reporting(E_ALL);

IronTree

Actually I'm not getting any errors, here is my code:

<title>
<?php if ($_SERVER['PHP_SELF'] == "page1.php")
{
	echo $row->something;
}
	    elseif ($_SERVER['PHP_SELF']=="page2.php")
		{
		    echo $row->something;
		}
	     else 
		{
		    echo ('Default Title'); } ?>
</title>

The $row->something; displays correctly in the given page. I'm just trying to call it to use it as a title. What happens is, it simply goes to the default.

rulian

echo out your $SERVER["PHP_SELF"];
look at what that is actually producing,
usually, if you want just the filename, do basename($SERVER["PHP_SELF"]);

kkobashi

It's likely that $_SERVER["PHP_SELF"] is "/page1.php" (note forward slash) instead of "page1.php" thus making your string compare incorrect.

phpinfo() can be your best friend in these kinds of issues

IronTree

kkobashi wrote:
It's likely that $_SERVER["PHP_SELF"] is "/page1.php" (note forward slash) instead of "page1.php" thus making your string compare incorrect.

phpinfo() can be your best friend in these kinds of issues

You are right, $_SERVER["PHP_SELF"] is producing /index.php. However, it is still passing over the conditional statement without errors.

laserlight

There should be no errors: it would just follow the conditional logic specified and print the wrong thing.

IronTree

laserlight wrote:
There should be no errors: it would just follow the conditional logic specified and print the wrong thing.

Okay, any suggestions on the proper logic to use? I was under the impression that I could reference objects much like variables any where in the script.

NogDog

<title><?php 
$fileName = basename($_SERVER['SCRIPT_NAME']);
if($fileName == "page1.php")
{
    echo $row->something;
}
elseif ($fileName == "page2.php")
{
   echo $row->something;
}
else
{
   echo 'Default Title';
   // For debugging:
   echo " (file name: $fileName)";
}
?></title>