[RESOLVED] Dynamically setting selected in drop-down

[Skor]

This one's puzzling me. I've created a page which lists inventory. At the top of the page is a drop-down menu/form which will allow visitors to filter their request. Here's my issue. After a selection is made, the form reverts to the top choice. The form posts to itself. I did some tinkering and it looks like the form variable is not there until the form posts. I've done some "testing" to verify when the variable is set. Isn't there a way to do this?? I've wound up putting in conditional subheads and a more descriptive first item so users can see what their search criteria was. Can this be done?

<FORM NAME="sort" method="POST" action="<?php echo $_SERVER['PHP_SELF']; ?>"> 
<SELECT NAME="earcode" onchange="this.form.submit();">
<OPTION VALUE="">Display the following Earrings...</option>
<OPTION VALUE="ALL">All Earrings </option>
<OPTION VALUE="E">Only Earwire Earrings</option>
<OPTION VALUE="P">Only Post Earrings</option>
<OPTION VALUE="L">Only Lever back Earrings</option>
</SELECT>

<noscript>
<input type="submit" name="earcode" value="Display Selected Earrings">
</noscript> ...

...$earcode = $_POST['earcode'];



if ($earcode =="ALL")...etc.

[etully]

Put this before the form:

$earcode = $_POST['earcode'];

Then change your option tags to this:

<OPTION VALUE=""<?php if ($earcode=="") { print " selected"; ?>>Display the following Earrings...</option>
<OPTION VALUE="ALL"<?php if ($earcode=="ALL") { print " selected"; ?>>All Earrings </option>
<OPTION VALUE="E"<?php if ($earcode=="E") { print " selected"; ?>>Only Earwire Earrings</option>
<OPTION VALUE="P"<?php if ($earcode=="P") { print " selected"; ?>>Only Post Earrings</option>
<OPTION VALUE="L"<?php if ($earcode=="L") { print " selected"; ?>>Only Lever back Earrings</option>

[Skor]

Perfect Solution, thanks!