[RESOLVED] PHP Script to read images (jpg's) in a folder and output their names

[Pulsorock]

Hello,

I need to make a simple PHP script that reads the content of a folder and looks for jpg files, the outputs the value as an xml.

For example, my folder is:
/var/www/mysite/images/

That folder contains 3 images:

• image1.jpg

• image_hello_2.jpg

• image_test_3.jpg

I need the PHP script to read that folder and output something like this

<image>
	<filename>image1.jpg</filename>
</image>
<image>
	<filename>image_hello_2.jpg</filename>
</image>
<image>
	<filename>image_test_3.jpg</filename>
</image>

I google for something similar, but couldn't find anything. I know that's probably just some few lines of code. So if anyone know how to do this and want to share it, I'll appreciate it.

Thanks in advanced...

[bostonmacosx]

Try:

$image_file_path = '/home/user/www/path/'; - this is the full server path to your images folder

$d = dir($image_file_path) or die("Wrong path: $image_file_path");
while (false !== ($entry = $d->read())) {
if($entry != '.' && $entry != '..' && !is_dir($dir.$entry))
$Images[] = $entry;
}
$d->close();

$images will be an array of your image filenames....

[jrolands]

you can try something like this

$i=0;
$img = scandir("directory/");
while($i<count($img)) {
	if(eregi("jpg$", $img[$i]) || eregi("jpeg$", $img[$i])) {
		echo("<image><filename>".$img[$i]."</filename></image>");
	}
++$i;
}

[Pulsorock]

Thanks... I combine both suggestions and came up with this:

$d = dir($full_path) or die("Wrong path: $full_path");
$i=0;
while (false !== ($entry = $d->read())) {

if($entry != '.' && $entry != '..' && !is_dir($dir.$entry))
$Images[] = $entry;

if(eregi(".jpg", $Images[$i]) || eregi(".jpeg", $Images[$i])) {
echo("<image>\n<filename>".$Images[$i]."</filename>\n</image>\n");
}

$i++;
}
$d->close(); 

Thanks for the help....