[RESOLVED] Fetching full URL?

john1704

Hi everyone,

I'm am trying to open a page's source code on the Internet using the function file_get_contents, and echoing the result (if you haven't already guessed, this is going to be a simplified proxy script).

However, the page doesn't appear like it should, mainly because the CSS file is missing. Here is the line of code that is causing me a problem:

<link media="all" href="css/home25.css" type="text/css" rel="stylesheet" />

Since the page has no idea where "css/home25.css" is, it thinks it doesn't exists and does nothing about it, so the page displays incorrectly.

How can I make it so that when a URL is posted to the page, PHP opens those CSS and .js files with their proper domain, like this:

<link media="all" href="http://www.proxifiedurl.com/css/home25.css" type="text/css" rel="stylesheet" />

Thanks.

Scriptmaker

http://www.php.net/str_replace

$newsourcecode = str_replace("css/home25.css", 
"http://www.proxifiedurl.com/css/home25.css", 
$oldsourcecode);

john1704

But see, the problem with using that is that I have no idea what people are going to enter. See, this is a proxy script, and I want to make it so that it will automatically replace those CSS files with actual posted URLs.

Scriptmaker

Look into "regular expressions", in this case, preg_replace. You'll have to have it search for code referring to local files...ie the "<link media="all" href="WHATEVER.css" type="text/css" rel="stylesheet" />" line ... and have it add the full url to the beginning, which you should just have stored in a variable anyway.

john1704

Of course! Why didn't I think of that in the first place? Thanks.