[RESOLVED] Display external page

mikawhat

I have a domain e.g. www.example.com and i want to display an external file on that page e.g. http://111.111.111.111/index.php

How can i do that?

I tried using fopen...

<?php
//file: www.example.com/getexternalpage.php
$fp = fopen("http://111.111.111.111/index.php", 'r');
echo $fp;
?>

... but i get an error message...

Resource id #7

Is my code correct? or it doesn't work with echo?

bpat1434

fopen, when read from the manual, will return a file resource, not the contents of the file (or the output). Hence, when you echo out the $fp variable, it tells you the resource information.

To read the page or whatever, you have to loop through it with a [man]while[/man] loop and inside that while loop, use [man]fread[/man] to read information from the stream.

Also, there is an easier way to get the page. If URL fopen wrappers are on (which they seem they are), then you can do:

$contents = file_get_contents('http://111.111.111.111/index.html');
echo $contents;

mikawhat

i used file_get_contents and it displays the page except of the images and the stylesheet, and also the links are not working. Is it possible to achieve what i want? to use an external page under my url, or i'm just wasting my time?

mikawhat

finally i made it with iframe...not bad! Thanks for your help mate.

bpat1434

it's possible, you just need to fix some things. one being that you need to search for images that don't start with http:// and add the base URL to the site to them. That way they're using the external image instead of trying to use your internal image. The same thing goes for the CSS file.