Insert break after 3 records?

kosmo101

trying to insert a break after 3 records are displayed in a table. the table can only hold 3 TD's wide so when the fourth record comes across a </tr> <tr> should be shoved in once and the next three displayed. Here is basic code...

foreach ($files as $file)
{
?>

<td align="center">... record 1 </td>

$i++;
}

So what happens if i do a limit 6 it puts all 6 in one TR. I need it to do 2 tr's with 3 td's in each.

Could someone tell me how to count the record it is on and if it is on record 4 to shove in </tr> <tr> once?

Php 4/mysql 4

Thank you Kevin

laserlight

Hint:
3 % 3 = 0
6 % 3 = 0
9 % 3 = 0

mpb001

What is really good with your response laserlight is the % operator is pretty unsearchable due to google ignores it.

I will give the operator in anagram format to make it easier.
slmdouu

Hint: write the letters in a circle, makes it easier

laserlight

I will give the operator in anagram format to make it easier.

lol, you're funny 🙂

kosmo101

must be over my head.

Is anyone able to yell me the code to put in?

thanks

laserlight

The basic idea is that if you are counting from $i = 1, then when $i divided by 3 leaves a remainder of 1, you need to begin a new row. When $i is perfectly divisible by 3, you need to end the current row.

Of course, after looping through the records you should check if $i is divisible by 3 one more time. If it is not, insert the required number of blank cells, then end the row.

Now, read the PHP manual on the Arithmetic Operators.

mpb001

laserlight wrote:
lol, you're funny 🙂

🙂

must be over my head.

Is anyone able to yell me the code to put in?

thanks

slmdouu = modulus( the searchable term for % )