Problem in Dynamic Form

yogendra

Hi all's

 First of all i would like to told you ,I am new in php i am just trying to make a simple application in PHP

Now my requirment is that i need to create a form dynamically . I am try to explain it .
 1: in form1     User will define how many form he want to fill now.
          ( Suppose he enter 3 )
  2: 3 form create automatically ( i call a row in loop )
  3 : Where loop end i just make a submit button.

Note : I define form just before loop.

 Now my problem is that how i will  be define its action .How i will be get the value of each field which is filled by user.

Plz help me if any one can. ( i can also write my code hare )

Thanks in Advanced.

jkurrle

Let me make sure I have this straight: You have a series of predefined forms that you want to access from a dropdown menu, correct? If so, I'd build a preliminary form who's action is to refresh back to itself. Then I'd look for the POSTed variable to determine which secondary form to load.

Here's an example:

$formval=$_POST['formval'];
echo "
  <form method=\"post\" action=\"samepage\">
  Select your form:
  <select name=\"formval\">
    <option value=\"form_1\">Form #1</option>
    <option value=\"form_2\">Form #2</option>
    <option value=\"form_3\">Form #3</option>
  </select>
  <input type=\"submit\" value=\"Select\">
  </form>
  ";

switch($formval)
  {
  case "form_1":
  echo "whatever the form is";
  break;

  case "form_2":
  echo "whatever the form is";
  break;

  case "form_3":
  echo "whatever the form is";
  break;

  default:
  //do nothing
  break;
  }