[RESOLVED] second expression of for loop

[Alpha1980]

for ($i = 0; $i < $var; $i++) {
     ...
     }

Look at the second expression of the above for statement:

$i < $var;

How do I change it to return $var only if $var is less than or equal to 6? And if $var is not less than or equal to 6, return 6?

In other words, something like this:

for ( $i = 0; $i < (if ($var <= 6) { $var } else { 6}); $i++ )

I am sure the syntax above is nonsensical but I hope it is clear what I want to do.

Thanks for helping.

[bradgrafelman]

What you're asking doesn't make sense.

Is $var being changed within the for() loop? If not, it will always be either <= or > than 6, so the for() loop will either run for an infinite amount of time or not at all.

[Alpha1980]

bradgrafelman wrote:

What you're asking doesn't make sense.

Is $var being changed within the for() loop? If not, it will always be either <= or > than 6, so the for() loop will either run for an infinite amount of time or not at all.

I don't want to change $var within the loop.

Please forget that and I'll try to explain a different way.

for ($i = 0; $i < $var; $i++) {
...
}

I want the above loop to execute a maximum of 6 times. So, if $var = 1, 2, 3, 4, 5 or 6, there is no problem. But if $var = 7 or more, there is a problem.

How do I limit the number of loop executions to 6?

[laserlight]

If you do not actually need a variable number of iterations, then just write:

for ($i = 0; $i < 6; $i++) {
    ...
}

If you do want to set an upper limit of 6 iterations, yet allow a variable number of iterations, then write:

for ($i = 0; $i < $var && $i < 6; $i++) {
    ...
}

[Alpha1980]

Thank you Laserlight. 🙂

Problem solved.

Thanks to Brad too.