Hi All,
Well Im still trying to figure out how to make stuff work so I can break it and then fix it again.
Just how I learn best. :o
I have (with some help) created a .php and successfully queried my db and displayed the results intelligently.
I have also created and attached a .css to pretty it up a bit. Not very pretty yet tho, just wanted to see it work! lol
I would like to be able to display those results on another .php.
Not sure what the "function/variable" or whatever its gonna be is called or how to draw resources from another page on the same server level.
Any help here would be greatly appreciated.
I would also like to know how to turn my resluts from any db query into a link.
<Very Very Lame Example>
$box2 = mysql_fetch_array (third.php/$results);
while ($box = mysql_fetch_assoc($results)) {
if ($box['number'] == 20 "<a href ="123.php">", echo $box['number'] , "</a>";
if ($box['number'] == 21 "<a href ="456.php">", echo $box['number'] , "</a>";
if ($box['number'] == 22 "<a href ="789.php">", echo $box['number'] , "</a>";
</Very Very Lame Example>
Here with: while ($box = mysql_fetch_assoc($results)) {
Im trying to get those $results from another page sitting next to this page and hold them in $box.
Am I on the right track here?
I hope this is clear enough to help generate some assistance. Im not asking for someone to write my code for me. Instead maybe just what "tags" am I looking for here and maybe an idea of how to fill in their () , ' ', " ", when I use them.
Once again,
Thank you very much for any help,
Bumba000
