[RESOLVED] Copy data from one select to another

DedoMraz

Hello all.

How can I copy selected data from select1 to select2 by pressing the "add" button.
Can I make this somehow without refreshing the page? (javascript, ajax etc.)

theelectricwiz

Hello. It can be done using javascript/ajax, but if you are wanting for the copy to show up on the page it may be easier just to refresh the page as you will have to copy a lot of items back and forth. To send the actual copy command you need to send the information required for the copy command to a php script as a get query in the link you request through ajax. eg something like.....

if (window.XMLHttpRequest) { // code for Mozilla, etc.
	xmlhttp=new XMLHttpRequest();
	xmlhttp.onreadystatechange=succFunction;
	xmlhttp.open("GET","http://localhost/copy.php?table=blah&items=1,2,3,6",true);
	xmlhttp.send(null);
} else if (window.ActiveXObject) { // code for IE
	xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
	if (xmlhttp) {
		xmlhttp.onreadystatechange=succFunction;
		xmlhttp.open("GET","http://localhost/copy.php?table=blah&items=1,2,3,6",true);
		xmlhttp.send();
	}
}

Hope that helps.

Cheers.

DedoMraz

theelectricwiz wrote:
Hello. It can be done using javascript/ajax, but if you are wanting for the copy to show up on the page it may be easier just to refresh the page as you will have to copy a lot of items back and forth. To send the actual copy command you need to send the information required for the copy command to a php script as a get query in the link you request through ajax. eg something like.....
if (window.XMLHttpRequest) { // code for Mozilla, etc.
	xmlhttp=new XMLHttpRequest();
	xmlhttp.onreadystatechange=succFunction;
	xmlhttp.open("GET","http://localhost/copy.php?table=blah&items=1,2,3,6",true);
	xmlhttp.send(null);
} else if (window.ActiveXObject) { // code for IE
	xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
	if (xmlhttp) {
		xmlhttp.onreadystatechange=succFunction;
		xmlhttp.open("GET","http://localhost/copy.php?table=blah&items=1,2,3,6",true);
		xmlhttp.send();
	}
}

Hope that helps.

Cheers.[/QUOTE]

Thanx. I resolvet it with javascript

bradgrafelman

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