[RESOLVED] value returning null - what am i doing wrong?

[sunshine66]

I have multiple form fields passing properly, except this one:

<select name="Day1Equip1" tabindex="84" class="small" >
   <option value="" ></option>
   <?PHP   include ("include/query_get_equip.php");	?>
</select>  

//where the include file contains

        $query3 = "SELECT * FROM EquipmentList ORDER BY Model";
        $result3 = @mysql_query($query3);
        while($line = mysql_fetch_array($result3))  
        {  
          $Model = $line["Model"]; 
          $Item = $line["ItemNum"]; 
          echo "<OPTION VALUE='$Model #$Item' >$Model #$Item</OPTION>";  
        }	

When I view the HTML source, the option values are correct.
For example "TEST #1", "TEST #2", "TEST #99" etc.

Upon posting the form with TEST #99 selected, javascript alert states $Day1Equip1 value is undefined while the php value returns null (i.e. '')

  $Day1Equip1 = $_POST['Day1Equip1'] ;
  print "$Day1Equip1";  //returns null value 

I have other select boxes with similar code, and their values pass properly.
I cannot figure out the problem with this one.

Any clues?

[bogu]

sunshine66 wrote:

Upon posting the form with TEST #99 selected, javascript alert states $Day1Equip1 value is undefined

How do you get the Day1Equip1 element value in javascript?

sunshine66 wrote:

the php value returns null

the value is null ([man]is_null[/man]) or [man]empty[/man]?
check if you don't have more elements with the same name in your form ...

[sunshine66]

That's exactly what the problem was. Problem solved when I corrected the duplicate name value.

AWESOME! THANKS!!!!