[RESOLVED] postage dropdown.

[benracer]

Hi,
I am trying to create a dropdown box that selects the postgae. I created this...

<?php
$pp = $_POST['charge'];
if (empty($pp)){
$pp = "next";}

if($pp == "next"){
$postage = 3.50;
echo "<option value=\"next\">Next Day Delivery &pound;3.50</option><option value=\"1\">1st Class &pound;2.00</option>";
}else if($pp == "sta"){
$postage = 2.00;
echo "<option value=\"sta\">1st Class &pound;2.00</option><option value=\"2\">Next Day Delivery &pound;3.50</option>";
}
?>

I cannot seem to get this to work after the first change. THANKS 🙂

[Kudose]

First: You set $pp as "next" but check for "nxt"

Second: I don't really understand what you're asking.

Third: It's against PHPBuilder's ToS to use commercial or profitable links in your signature.

[benracer]

Ok, i have a dropdown box where the user can select £3.50 or £2.00. When a value is chosen i would like that one to be the one displayed therefore it needs to be top. Also i need the variable postage to be chosen. Many Thanks, Ben

[rsmith]

I don't really get it either. When a user chooses something from a drop-down menu it's going to be at the top. Why don't you just simplify it?:

<select name="postage">

<?
     $pp = $_POST['charge'];
          if (empty($pp)){
               $pp = "next";
          }

  if($pp == "next"){
           echo "<option value='next' selected>Next Day &pound3.50</option>"; 
           echo "<option value='1st'>1st Class &pound2.00</option>";
  }else{
           echo "<option value='1st' selected>1st Class &pound2.00</option>";
           echo "<option value='next' selected>Next Day &pound3.50</option>"; 
  }
?>

</select>

If $pp has a wide range of potential values, I would use a switch() to determine which order to put the options in.

[benracer]

Thanks, Its sorted now. The error was in the else both options are set as selected. 😃

[Kudose]

You are still using a signature against the ToS.