[RESOLVED] echo 4 lines per row

[zbyke]

if this has already been posted sorry...did a search but couldn't find it.

I'm trying to make a table to list 4 rows per line.
<table><tr>
<td>MY IMAGES</td>
</tr></table>

the line
"<td>MY IMAGES</td>"
is the line that I want to grab from mySQL and post it 4 times per line.
I'm guessing it's an array but not sure and if it is I don't know how to set that up. I've only messed with very basic coding... Can anyone help me with this please?!

[rsmith]

Someone had this same question and my answer helped them so here it is again.

++$x;
							if($x % 4 == 1){
								echo '<tr>';
							}
						$full = str_replace("_thumb.png",".png", $file);
						$size = getimagesize($img_path.$full);
						$width= $size[0] + 25;
						$height= $size[1] + 25;

					echo '<td>MY IMAGE STUFF GOES HERE</td>';
						if($x % 4 == 0){
							echo '</tr>';
						}

[niroshan]

just replace the array with the result set.

<table border="0" width="100%">
$arr = array('test1','test2','test3','test4','test5','test6');

$x=0;
while(list($name,$val)= each($arr))
{
	if($x==0)
	{
		print '<tr>';
	}

print '<td>'.$val.'</td>';

$x++;

if($x==4)
{
	print '</tr>';
	$x=0;
}
}

if($x<>0)
{
	$rest = 4-$x;
	for($i=0;$i<$rest;$i++)
	{
		print '<td>&nbsp;</td>';
	}
	print '</tr>';
}

</table>

[zbyke]

yeah I figured it out about an hour or so later...forgot to post sorry.
what I did was

$x = 0;
echo "<center><table><tr>";
$data = mysql_query("SELECT * FROM admin_modules ORDER BY id") or die(mysql_error());
$info = mysql_fetch_array($data);
while($info = mysql_fetch_array($data)) {
$x++;
echo "
<td width=\"80\" height=\"80\">
<a href=\"index.php?name=".$info['module_name']."&file=".$info['file_name']."\"><img src=\"/admin/modules/Admin/images/".$info['module_icon']."\"></a></td>";
if(!($x%4)){echo "</tr><tr>";
}
}
echo"</tr></table></center>";