Get filename from where function is called?

TitanKing

Hi everyone,

Thanks for looking at my thread.

Say I have a file func.php, in the file I have a function, lets call it...

called_from_file()

Now I include and call func.php in another file called app.php, I would like for called_from_file() to know from which file I called him.

Thanks for any direction on this issue.

Regards

Weedpacket

So if you call called_from_file() in app.php it will return "app.php", and if you call called_from_file() in func.php it will return "func.php"?

That is what the magic FILE constant does without needing any function.

TitanKing

Weedpacket wrote:
So if you call called_from_file() in app.php it will return "app.php", and if you call called_from_file() in func.php it will return "func.php"?

That is what the magic FILE constant does without needing any function.

Thanks for the reply, strangely enough this does not work, it only shows func.php, does not matter from where I call it... 🙁

owaring

what if you pass FILE to the fumction?
ie

<?php
function cal_func($file)
	{
	echo 'hello world im at'.$file;
	return;
	}
?>

<?php
include ('this_file.php');
cal_func(__FILE__);
?>

TitanKing

owaring wrote:

what if you pass FILE to the fumction?
ie

<?php
function cal_func($file)
	{
	echo 'hello world im at'.$file;
	return;
	}
?>

<?php
include ('this_file.php');
cal_func(__FILE__);
?>

Hi, thanks for the reply, this seems to be the only solution, I was hoping for an automatic solution as this will be used allot and needs to be kept as short as possible, but I guess beggars cant be choosers 🙂

I am going to keep the thread unsolved, perhaps someone has an easier solution.