[RESOLVED] variable issue

[slimjim]

Can anyone tell me why this variable is not working in this code ?

$ROOT="http://www.mysite.com/new";

$rating=$rating."<img alt='$imrating' src='$ROOT/images/starn.gif'>";

$ROOT is not working as a variable in the rating line.

Now I can hardcode it and it works, but I need the variable to work in that line.
ROOT need to work because I am using basically fake directorys, for search friendly urls.
So ROOT variable is important to work.

I tried ".$ROOT." and also with a single qoute as well, so if you know what I am doing wrong please help.

[bradmasterx]

define("root", "http://www.mysite.com/new", false);

$rating=$rating."<img alt='$imrating' src='".ROOT."/images/starn.gif'>";
echo $rating;

[slimjim]

Can you tell me why it needed to be defined that way in order for it to work, cause that worked.

[tank]

You don't necessarily need to define a constant to make it work.

slimjim, your way should have worked too. Maybe PHP is not detecting the variable within the double quotes right. Use curly braces around the variable so the PHP parser can find it. Don't worry, the curly braces will not be a part of the value (end result).

$ROOT="http://www.mysite.com/new"; 

$rating=$rating."<img alt='$imrating' src='{$ROOT}/images/starn.gif'>"; 

[slimjim]

Your right, thank you