opening a file with a partially known filename

AsaSchool

Hey everyone,
I have a problem with trying to open a zip file that has a changing name. The file always starts with the same first 4 letters and an underscore followed by 4 random letters or numbers and always ends in .zip:

Example:
FILE_DG01.zip - Today
FILE_9044.zip - Tomorrow
FILE_809P.zip - Next Day........

I use the following simple script to extract the files and move them to another directory where I use them in my applications:

<?php
$zip = zip_open("FILENAME.zip");
if ($zip) {
while ($zip_entry = zip_read($zip)) {
$fp = fopen("DIRECTORY".zip_entry_name($zip_entry), "w");
if (zip_entry_open($zip, $zip_entry, "r")) {
$buf = zip_entry_read($zip_entry, zip_entry_filesize($zip_entry));
fwrite($fp,"$buf");
zip_entry_close($zip_entry);
fclose($fp);
}
}
zip_close($zip);
}
?>

I have looked everywhere for an answer and I am sure that I am looking in the wrong places for the solution to this. Any help is appreciated.

Thanks

Weedpacket

[man]glob[/man]. That will tell you what choices you have.

AsaSchool

thanks weedpacket.
I just looked at the function and that appears to be what I need.

Thanks.

NogDog

It's also one of my favorite function names. 🙂

AsaSchool

I have altered my code to reflect the call to the glob function but the file is either not being passed or the file is not found.

<?php

$match = glob("/zip/{*.zip}", GLOB_BRACE);
$zip = zip_open('' . $match . '');
if ($zip) {
while ($zip_entry = zip_read($zip)) {
$fp = fopen("../zip/".zip_entry_name($zip_entry), "w");
if (zip_entry_open($zip, $zip_entry, "r")) {
$buf = zip_entry_read($zip_entry, zip_entry_filesize($zip_entry));
fwrite($fp,"$buf");
zip_entry_close($zip_entry);
fclose($fp);
}
}
zip_close($zip);
echo "COMPLETED $zip";
}
?>

any other thoughts on how to achevie this. The file I need to access is named like this: FILE_9999.zip. I tried the following alternate calls to glob as well:

$match = glob("FILE_*.zip");

$match = glob("*.zip"); - this would access 4 files on the server. I need to call them individualy so the best way for me to do this is to be able to use a way to search by the 4 wildcard digits ---FILE_????.zip

Thanks again

NogDog

A couple things:

glob() returns an array of matches, so you'll need to walk through the array; you can't use the result directly as a file.

The matches returned will include any path information you used as the "search" string, so if you do glob('directory/subdir/*.zip'), the resulting matches will be something like "directory/subdir/filename.zip', not just 'filename.zip'. (You can use the [man]basename[/man] function if you want to trim off the directory info.)

In your sample code, note that '/zip/' is different than '../zip/', with the former looking for a directory "zip" just under the root directory of the file system, while the latter is looking for it under the directory just above the current working directory.

Anyway, if you know the file will be "FILE_9999.zip" format, then you could do something like:

$matches = glob('../zip/FILE_*.zip');
if(count($matches) == 1)
{
   echo "The file is: " . basename($matches[0]);
}
elseif(count($matches) == 0)
{
   echo "No file found.";
}
else
{
   echo "Multiple matches found: " . implode(', ', $matches);
}

AsaSchool

thank you for your time. That worked perfect in my script and is finding the files I need.

Thanks again for your time and input