Easy IF statement answer I think!?

[didster]

Hi,

How do I say, if $contactname is empty, do not print it? It sounds easy but maybe I am not getting the syntax right. The following code works when just printing the variable in an email. Cheers...

"\n\n-- Contact Name --\n\n" .
$contactname .

[laserlight]

if (!empty($contactname)) {
    echo "\n\n-- Contact Name --\n\n" . $contactname;
}

[didster]

Thankyou!

[didster]

Almost there but again I must have my syntax wrong somewhere as the php is not working. Do I put the if statement in brackets? Can or should I do it this way (checking for empty fields within the message?) Thank you

$message .=

"\n\n-- Chk --\n\n" .

$_POST['chkno'][0] .
$_POST['chkno'][1] .
$_POST['chkno'][2] .

if (!empty($contactname)) {
    "\n\n-- Contact Name --\n\n" . $contactname;
}

[bakerng]

Try this...

$message .=

"\n\n-- Chk --\n\n" .

$_POST['chkno'][0] .
$_POST['chkno'][1] .
$_POST['chkno'][2] ;

if (!empty($contactname)) {
    $message .= "\n\n-- Contact Name --\n\n" . $contactname;
}

[didster]

I'm afraid it still returns a blank screen, I really need to read up on syntax and PHP in general! Thank you for the replies though

[didster]

Solved it! How do I say that I have solved it? Not sure how mind!

[laserlight]

Click on "Mark Thread Resolved" under the "Thread Tools" option in the menu bar above.