Strip blank lines

zzz

I run a loop and put some lines into a var.

$count = $n;		

while($count > 0){
$List .= $var[$n]."<br>"; 
$count = $count - 1;

}

echo $List;

So I get something like this:

Line 1 asdasdasd
Line 2 sdasd asdasda

Line 4 sSASASAS

Line 6 asdasdasd

Now, I'd like to strip the blank lines. I tried doing:

$List = preg_replace("/(^[\r\n]*|[\r\n]+)[\s\t]*[\r\n]+/", "\n", $List);
}

But it still outputs the blank lines... Any suggestions?

😕

NogDog

How about . . .

$List = preg_replace('/(\r?\n)([\ \t]*\r?\n)+/', "$1", $List);

. . . ?

arty56

$List .= $var[$n]."<br>";

What about a simple query that asks if $List has anything in it before printing.

if (!$List){
//ignore if empty
}
else{
echo("$List");
}

NogDog

arty56 wrote:
What about a simple query that asks if $List has anything in it before printing.

if (!$List){
//ignore if empty
}
else{
echo("$List");
}

I didn't notice before that the "<br>" was being inserted, so if you do it the preg_replace() way you would have to look for it, too. I agree though that it might be simpler just to avoid appending empty values in the first place.

classix16

ucan use str_replace function
ex:
$the_string="a b c d e";
// the output should be $the_string="abcde"

then do this:
$the_string=str_replace(" ","",$the_string);

🙂
sorry if i'm wrong

zzz wrote:
I run a loop and put some lines into a var.
$count = $n;		

while($count > 0){
$List .= $var[$n]."<br>"; 
$count = $count - 1;

}

echo $List;
So I get something like this:

Now, I'd like to strip the blank lines. I tried doing:
$List = preg_replace("/(^[\r\n]*|[\r\n]+)[\s\t]*[\r\n]+/", "\n", $List);
}
But it still outputs the blank lines... Any suggestions?

😕