[RESOLVED] Subtracting date/time

mhodge87

I should've posted this in the other thread, but anyway I have a time stamp

LogonTime: 20080510053516
Current Time: 20080510042225

They are in YYYYMMDDHHMMSS format.

So how would I determine the log on time. I tried Subtracting them, but It hasn't been giving me correct figures. My guess would be to pick out the hour/minute/sec part and convert those into seconds to be inserted into a table. Just doing that is what is stumping me.

NogDog

You can convert it to a unix timestamp (seconds) with:

$timeStamp = '20080510053516';
$unixTime = strtotime($timeStamp);

mhodge87

Then subtract them and convert them back? or do I not need to reconvert them?

leatherback

wat do you want to know of it?

If you want the time since logon: If you convert it and substract the current time from it, you would have the number of seconds since logon.

mhodge87

$LogonTime = strtotime("20080510053516");
  $CurrentTime = strtotime("20080510042225");
  echo $LogonTime-$CurrentTime;

When I do that its putting out 65059200. Am I not doing something correct?

mhodge87

I think I figured it out:

I did the following:

$LogonTime = gmmktime(05, 35, 16, 05, 10, 2008);
  $CurrentTime = gmmktime(04, 22, 25, 05, 10, 2008);
  echo $LogonTime-$CurrentTime;

That worked. Thanks for the help.