A Simple Upload and Image Display code?

ChristieLuv

Hi! I'm trying to find a basic PHP code that uses an HTML form to upload an image to a specified directory and after that the image address can be called for displaying the image with PHP or putting it in a textarea box for linking. I know it seems simple but I've been looking everywhere for one. I must be looking in the wrong places. If anyone can give any help I would so appreciate it!

Thank you!

leatherback

Hi,
welcome to phpbuilder.

I think you might have to write it yourself. As there are only a few small components in such a script, the config of which is very much dependent on your personal preference and server setup, it is probably not worth for most people to put such a script online.

I do not know your skill level when it comes to PhP as this is your first post, and not in newbies. Feel free to post if this doesn't help you at all (If for instance I could just as well be telling you fly to the moon; it is just not gonna happen ;-))

leatherback

an upload script, to get you started:



   $original_picture = $file_array['name'];         // original filename
   $tmp_picture      = $file_array['tmp_name'];     // Filname in upload folder
   $new_picture      = $destination;                // full path filename

    // Test variables / files for correct input 

    if (!file_exists($tmp_picture) )         // Check whether filesource exists
      {
      return(array(0=>false, 1=>"File doesn't exist in temporary folder on server!"));
      // The script has died here
      }

    //Get file details **************************        
    $size = GetImageSize($tmp_picture);

	// error trapping
	if($size === false)
	  {
	  return(array(0=>false, 1=>"Not a valid fileformat."));
	  }

    if($size[1] * $size[0] > 1000000)
	  {
	  return(array(0=>false, 1=>"<h1>Unsuccesfull upload</h1>.Please reduce the size of your image. At the moment we can only accept images of 1000*1000 pixels max."));		  
	  }
    $aspectRat = (float)($size[1] / $size[0]);

    if(file_exists($new_picture))        // Remove existsing file
      {
      $delete = @unlink($new_picture);
      }


    // Calculate new x/y size, maintaining original aspect ratio

    if( ($size[0] <= $new_max_width) && ($size[1] <= $new_max_width) )  // Image < max size
      {        
	  // Just copy and use as is
      copy($tmp_picture, $new_picture); 
      $newX = $size[0];
      $newY = $size[1];
      }
    else 
      {	// Figure out how to resize

      $width_ratio = $size[0] / $new_max_width;
      $height_ratio = $size[1] / $new_max_height;

    if($width_ratio >= $height_ratio)  // width needs to be reduced more
      {
      $newY = $new_max_width * $aspectRat;
      $newX = $new_max_width;
      }
    else
      {
      $newY = $new_max_height;
      $newX = $new_max_height * (1/$aspectRat);
      }


    //create the destination image resource. 
    $destImg = ImageCreateTrueColor($newX, $newY );

    //read the source image (original), use correct function depending on format	

    if ($size[2] == 1)
      {
      $sourceImg = ImageCreateFromGIF($tmp_picture);
      }
    else if($size[2] == 2)
      {
      $sourceImg = ImageCreateFromJPEG($tmp_picture);
      }
    else if ($size[2] == 3)
      {
      $sourceImg = ImageCreateFromPNG($tmp_picture);
      }
    else
      {
      return(array(0=>false, 1=>"This file cannot be used. It is not a jpg, gif or png file.<br />"));
      }

    // Create the new output file *******************

//  print 'pos4: '. memory_get_usage  ();
        imagecopyresampled($destImg, $sourceImg, 0, 0, 0, 0, $newX, $newY, $size[0],  $size[1]);
//  print 'pos5: '. memory_get_usage  ();

    imagejpeg($destImg, $destination);
//  print 'pos6: '. memory_get_usage  ();
        }

    // Remove the temproary file *********************
    if($remove_orig == 1)
      {
      $deletedfile = @unlink($tmp_picture);
      }

ChristieLuv

Hi Leatherback, thank you so much for your help! I'm am a beginner do you think this should be moved to the newbies forum?

Is the code above the processing script to send the HTML form to? If so I was wondering if I should give my HTML form certain names and id's in the inputs to connect to the script. Also is there a place to put the address of the destination folder?

🙂

leatherback

hi Christy,

unfortunately, this is only the upload section of it, basically it uses a $file_array, which is -in my scripts- a verified $_FILES array with the information on the file that is being uploaded. The form, the email and stuff like are all separately.

As you are a complete freshling in coding, I would suggest you start of by making a form, and getting the variables from that form to display on the next page, and take it from there. The best way to start this stuff is in small doses; trying to write this in one go might get you desperate and ready to give up, just because it is all new, and stuff.

Have a look at the coding tips (below) which links to short simple tutorials for a series of simple basic tasks that you would like to know when you do these things, I think. (I do apologize for a few errors in there, and the slow loading of my page. I transferred hosts, anbd now my scripts have not enough memory: I need to rewrite some stuff of the site).

ChristieLuv

Oh thank you so much! I'll check out those tutorials. I know HTML really well but only know PHP a fairly. I couldn't make too complicated codes at the moment. This has been very helpful.

🙂