Form validation

tua1

Hello

I am a newbie in PHP and sorry about my english.

I have a problem with form validation, I wrote a script to check length of password,
but no matter what I input the function returns always that the pass is too short.

This is a code:

if (strlen($_SESSION['pass1']) <6) {
	resendToForm("?flg=purple");
	}

I don't know what I am doing wrong.

Could anybody help me?

NogDog

Perhaps that should be $POST instead of $SESSION if you're checking the form data?

peytonrm

Your logic looks fine. I think you should probably be checking $POST instead of $SESSION. The post variable is what automatically gets populated on form submission. Session will not get populated unless you manually put something in it or have data coming in from a cookie.

By the way, your english is better than that of a lot of the native speakers I've met 🙂.

tua1

peytonrm wrote:
By the way, your english is better than that of a lot of the native speakers I've met 🙂.

Thanks, but this is only basic words, which are remember from primary school when I

studied english🙂

Anyway thank you for your responds, but I think the problem lies somewhere else,
because my other script like

 if ($_SESSION['pass1'] != $_SESSION['pass2']) {

 resendToForm("?flg=pink");

if (!ereg('^[a-zA-Z0-9_\.\-]+@[a-zA-Z0-9\]+\.[a-zA-Z0-9\_\.]+$', $_SESSION['email'])) 
	{
	      resendToForm("?flg=green");
	}

works fine.

So maybe there is another solution..

tua1

I use $_POST and the problem no longer exists.

Anyway I have a next problem, mabe I am blind but I can't figured out what is wrong

$query3= "GRANT SELECT, INSERT, UPDATE, DELETE "
	."ON klienci_id, klienci_adres, zamowienia, zamowienia_pozycje, opinie "
	."TO ".$arVals['login']." IDENTIFIED BY '".$arVals['pass1']."';"

I have an error:

Parse error: syntax error, unexpected T_VARIABLE in C:\WebServ\httpd\Runners2\scripts\register.php on line 330

Anyone help??

Greetings

NogDog

Swap the final semi-colon and quote:

$query3= "GRANT SELECT, INSERT, UPDATE, DELETE "
	."ON klienci_id, klienci_adres, zamowienia, zamowienia_pozycje, opinie "
	."TO ".$arVals['login']." IDENTIFIED BY '".$arVals['pass1']."'";

tua1

little semicolon 😃 ;

thank you!

But if I try this:

	$query3= "GRANT SELECT, INSERT, UPDATE, DELETE "
    ."ON table1, table2, table3, table4, table5 "
    ."TO ".$arVals['login']." IDENTIFIED BY ".$arVals['haslo1']."";

I have a syntax error: Invalid query: Something is wrong in your syntax obok ' table2, table3, table4 , table5 TO user1 IDENTIFIED BY 'pass1' w line 1

However if I try this:

$query3= "GRANT SELECT, INSERT, UPDATE, DELETE "
    ."ON table1"
    ."TO ".$arVals['login']." IDENTIFIED BY ".$arVals['haslo1']."";

This is works, so I don't know why the first statement doesn't work.

Any advices?

Regards