[RESOLVED] getimagesize() Problem

[Ne_OnZ]

Hello, my script doesn't seem to want to work correctly. I have a form where a user can put in an url to link an avatar to my site. I wanted to check the dimensions, if it's greater then 100x100, then resize it. Here's what I have:

$size = getimagesize($avatar['avatar']);
	if($size[0] > "100" || $size[1] > "100") {
	     echo "' alt='' class='bigav' /></p>";
	     $over = "1";
	}
	else {
	     echo "' alt='' /></p>";
	}

$avatar['avatar'] is the way I get the url from the database. I tried to echo the $size[0] and [1] to see how the dimensions are shown, but it didn't echo anything. So I'm guessing the getimagesize() is wrong somehow. Any help would greatly be appreciated!

Thank You! 🙂

[NogDog]

Do you get any error messages displayed or in the error log? What I'm suspecting is that the [man]url_fopen[/man] configuration option is not enabled (or you are using a PHP version older than 4.0.5, which is when the URL option was added for the file parameter).

You could try adding the following lines to the script before the call to the function to see if it tells you anything more:

ini_set('display_errors', 1);
error_reporting(E_ALL);

[Ne_OnZ]

I am using php 4.4.2, should be upgraded to PHP5 tomorrow. Anyways, I tried your code and I got no errors.

Here's the whole code, might be some mistake here that I don't see:

if($_SESSION['username']) {

   $sql = "SELECT avatar FROM users WHERE username = '".$_SESSION['username']."'";
   $res = mysql_query($sql) OR die(mysql_error());

echo 	"<form action='#' method='post'>
	<fieldset id='account'>
	<legend>You can change your avatar here.</legend>
	<br />
	<div class='create' style='width: 300px'>
		<br />Your Current Avatar:<p>
		<img src='";

while($avatar = mysql_fetch_array($res)) {
     echo $avatar['avatar'];
 }

$size = getimagesize($avatar['avatar']);
if($size[0] > "100" || $size[1] > "100") {
     echo "' alt='' class='bigav' /></p>";
     $over = "1";
}
else {
     echo "' alt='' /></p>";
}

if($msg == "1") {
    echo "<p class='red'>Your avatar has been changed!</p>"; }
if($over == "1") {
    echo "<p class='red'>Your avatar was resized to 100x100.</p>"; }

echo	"</div>";

Thank You Again!

[NogDog]

Have you echoed out $avatar['avatar'] to ensure it is a full URL (including the "http://" portion)?

PS: I tried this locally and it worked OK:

<?php

$sizeInfo = getimagesize('http://charles-reace.com/image/noggin.jpg');
echo "<pre>".print_r($sizeInfo,1)."</pre>\n";

?>

[Ne_OnZ]

Yes I have echoed out the $avatar['avatar'], it is the full URL. The thing with local url is that I don't know what URL the user will submit. So that just wouldn't work.

I tried echo "<pre>".print_r($size,1)."</pre>\n"; and it still echoed nothing. 🙁

Thank You Again!

[Ne_OnZ]

I figured out what was wrong. Apparently I was only able to use $avatar['avatar'] inside the while statement. So I assigned it to a variable and it works like a charm now!

Thank You for all your help! 🙂