[RESOLVED] Another date question

[yorktown]

I have a website where I display two days:

$month="July";
$dayone=10;
$daytwo=$dayone+1;

so:
echo "$month {$dayone}-{$daytwo}, 2008";
outputs as:

July 10-11, 2008

My question is, what is if it is the end of the month? How do I get PHP to recognize that:

July 31-1, 2008

.....won't work and it needs to be

July 31-August 1, 2008

How do I do this?

Thanks

Marc

[whiterabbit]

yorktown wrote:

I have a website where I display two days:

$month="July";
$dayone=10;
$daytwo=$dayone+1;

so:
echo "$month {$dayone}-{$daytwo}, 2008";
outputs as:

July 10-11, 2008

You can use strtotime - it is a php function.

So before doing:

echo "$month {$dayone}-{$daytwo}, 2008";

You could do :

$date_1 = $month . " " . $dayone . ", 2008"; // this will get the current date in a 
string form

$date_1_ts = strtotime($date_1); // this will convert $date_1 into a timestamp
$daytwo = date('j', strtotime("+ 1 day", $date_1_ts)); // since you are working
 with time stamps, when you add a day to the end of the month, it increments the
 month automatically - of course you will have to format the date to what you 
want in the date function

Hope this helps.

[yorktown]

Thanks