function problem

djwideboy

I am having a problem getting a date to be made inside a for loop

can anyone help me?

Iam trying to make the for loop work so that it works out and outputs every year between 2 dates and for some reason i cant get it to work.

function dateyear()
{
$thisyear = date("Y");
$takeaway = "17";
$takeaway2 = "100";
$num2 = $thisyear -= $takeaway2;
$num1 = $thisyear -= $takeaway;
for ($yer=1; $yer<$num1; $yer--)
{
echo '<option value="' . $yer . '">' . $yer . '</option>';

}
}

intenz

Something like...

<?php
function dateyear()
{
	$year1 = 2008;
	$year2 = 2018;

for( $i = $year1; $i <= $year2; $i++ )
{
	echo '<option value="' . $i . '">' . $i . '</option>';
}
}

dateyear();
?>

djwideboy

The only problem is i need the system to work out the datesfro 17 years ago to 100 years ago but it will auto update every year so for example

1991
1920

something like that?

Any ideas.

I thought that i could use a simpe date function and do the math but i cant get it to work.

djwideboy

function dateyear()
{
$thisyear = date("Y");
$takeaway = "17";
$takeaway2 = "90";
$num2 = $thisyear -= $takeaway2;
$num1 = $thisyear -= $takeaway;
for ($i= $num2; $i<= $num1; $i++)
{
echo '<option value="' . $i . '">' . $i . '</option>';

}

echo $num1;

}

i have tried to used a change of variable $num(1/2) but i cant seem to get the above to work?

Horizon88

Do you want a function to calculate all the years between two given dates? If so, this should do it:

<?PHP

function find_years($year1, $year2) {
    $return = false;
    if ($year2 >= $year1) {
        $diff = $year2 - $year1;
        $return = array();
        for ($i = 0; $i <= $diff; $i++) {
            $return[] = $year1+$i;
        }
    }
    return $return;
}

print_r(find_years('1990','2008'));

?>

Returns either boolean false or an array of all the years in increasing order.

Edit: The above code snippet outputs this, btw:

Array
(
    [0] => 1990
    [1] => 1991
    [2] => 1992
    [3] => 1993
    [4] => 1994
    [5] => 1995
    [6] => 1996
    [7] => 1997
    [8] => 1998
    [9] => 1999
    [10] => 2000
    [11] => 2001
    [12] => 2002
    [13] => 2003
    [14] => 2004
    [15] => 2005
    [16] => 2006
    [17] => 2007
    [18] => 2008
)

Edit: I've re-read the thread three times now, and I'm still not sure what you want. This is a pretty simple function, though - all you'd need to do to do what I think you're asking to do would be something like $years = find_years($first_year, date('Y')); where $first_year is the first year you want to start at (something about seventeen years ago? - $first_year = date('Y') - 17; ) and the second argument is the last year you want to show (date('Y') being the current year). Let me know if that helps 😃

djwideboy

i wanted to display the items in a form or in this particular case a select option box. I am only anovice so your code has confused me a little.

For some reason when i do the mathmatics it wont keep the values and insert them in place of the variables.

Horizon88

What my code will do is return an array of all the years in your range - you pass in the two years you want between like I have in the example, then it returns the array with all the years in it. To put them into a select box you'd do something like:

$years = find_years(2000, 2008);
echo '<select name="years">';
foreach ($years as &$value) {
   echo '<option value="'.$value.'">'.$value.'</option>';
}
echo '</select>';

djwideboy

I do want the code to calculate between to given dates but the dates will change as the years go on. This code will offer a select menu that will always make sure the person who fills it in cant be younger than 18 years old.

That why i need to use the $thisyear = date("Y"); function then i do the maths to produce the date

Ive echoed out the statement to ensure the values are outputed but for some reason i cant get the values to work during the function.

Horizon88

So put date("Y") as an argument for the function I wrote. If you want to find the range of 18 years before current, do something like this:

$this_year = date('Y');
$range = find_years($this_year - 18, $this_year);

With the code I posted above.