[RESOLVED] Day of the year to date

[mark_kccs]

Hi All

I am using the date function to get the day of a year as in

$stt = strtotime('01-01-2008');
$day_of_year = date('z', $stt);

which gives 0 and 31-12-2007 would give 364. Does anyone know of a function or method that might give the date based on the day of the year and the given year?

What i mean here is if I pass 364, 2007 I should get something like 31-12-2007.

Many thanks in advance.

[laserlight]

You could use [man]explode/man and [man]strtotime/man, e.g.,

$day_year = explode(',', '364, 2007');
echo date('d-m-Y', strtotime('1 January ' . $day_year[1] . ' + ' . $day_year[0] . ' days'));

[mark_kccs]

Hi laserlight

Many thanks, worked like a charm.

Have a great day.

[Weedpacket]

Hmmm...

$z = 142;
$y = 2008;
echo date('z', mktime(0,0,0,1,$z+1,$y));

Thanks for reminding me about mktime's argument order. 🙂