Parse error: syntax error, unexpected T_VARIABLE, expecting ';' i

[ameen]

Hi, I could not solve this problem as stated below.

Parse error: syntax error, unexpected T_VARIABLE, expecting ';' in C:\Program Files\EasyPHP 2.0b1\www\library\config.php on line 71

Appreciate if anyone solve it. Line 71 I have bold it. Thanks

if (!get_magic_quotes_gpc()) {

if ( (isset($POST)) && (!isset($POST['txtQty'])) && (!isset($POST['hidCartId'])) && (!isset($POST['hidProductId'])) )
{
foreach ($POST as $key => $value)
{
$POST[$key] = trim(addslashes($value));
}
}

// txtQty[]

if ( isset($POST['txtQty']))
{
$countQty = count($POST['txtQty']);
for($i = 0; $i < $countQty; $i++)
{

      $valQty = $_POST['txtQty'][$i];
  $_POST['txtQty'][$i] =  trim(addslashes($valQty));
  }

}

[NogDog]

I copied and pasted your code into my editor and got no parse errors (after I added a final "}" at the end to close the initial if block).

PS: You can make your code snippets much easier to read and analyze if you wrap them with the board's [noparse]

 . . . 

[/noparse] tags.