Read the first part of a file name

joane1

hi all

i have a directory that contains more files:

034.php
second.txt
3_4555.xls
53.doc
521.doc
.....

How can i do read and print only those files that begin with (e.g.) "53"?

NogDog

$dir = '/path/to/directory';
$files = glob($dir . '/53*');
echo "<pre>".print_r($files, 1)."</pre>";

joane1

ok, sounds good.
But how can i assign the values (file names) to one or more variables?

i tried this, but it shows only one value:

echo $files[0];

bodzan

$dir = '/path/to/directory';
$files[] = glob($dir . '/53*');

This way you would get an array of these values in $files array, so you could list them through array listing functions...

NogDog

joane1;10877513 wrote:
ok, sounds good.
But how can i assign the values (file names) to one or more variables?

i tried this, but it shows only one value:

echo $files[0];

Not sure I follow, but $files will be an array of matches that you can traverse that via a [man]foreach[/man] loop, or use any of the many array functions to further manipulate the array. For instance, if you wanted a list of links:

<ul class='file_list'>
<?php
foreach($files as $file)
{
   echo "<li><a href='".$file."'>".basename($file)."</a></li>\n";
}
?>
</ul>