Ajax attempt

[LiamBailey]

Has anyone got any ideas what is wrong with the below, my first ever attempt at an ajax script. Maybe it can't be used in this way?

function sitemap()
{
var urls = '
<?xml version="1.0" encoding="UTF-8"?>
<urlset xmlns="http://www.sitemaps.org/schemas/sitemap/0.9">';
link = "";
 links = document.anchors.length-1;
  for (loop = 0; loop < links; loop++)
    {
		link = document.anchors[loop].href;
		urls += '<url><loc>' + link + '</loc></url>';
		}
urls += '</urlset>';
if (window.XMLHttpRequest)     // Object of the current windows
{ 
    xhr = new XMLHttpRequest();     // Firefox, Safari, ...
} 
else 
 if (window.ActiveXObject)   // ActiveX version
 {
    xhr = new ActiveXObject("Microsoft.XMLHTTP");  // Internet Explorer 
 } 
 var url = "test.php";
 var params = "sitemap=" + urls;
 xhr.open("POST", url, true);

//Send the proper header information along with the request
xhr.setRequestHeader("Content-type", "application/xml");
xhr.setRequestHeader("Content-length", params.length-1);
xhr.setRequestHeader("Connection", "close");
xhr.send(params);
}

[NogDog]

If you want to type newlines within a JavaScript string literal (or otherwise break a single command over multiple lines) you have to escape the return with a "\", e.g.:

var urls = '<?xml version="1.0" encoding="UTF-8"?>\
<urlset xmlns="http://www.sitemaps.org/schemas/sitemap/0.9">';

(This is because, unlike PHP, the terminal ";" is optional, so the JS parser treats an un-escaped newline as an end-of-command character.)