Determining how to print a number

jpoladsky

I want to make a function that determines how to print a number pulled from a database. The number represent the number of baths in a house. So, the number will either be a whole number or have .5 decimal (a half bath).
What I want is if the house has no half bath for it to print the number with no decimal so if the number is 2.0 I want it to print 2, but if the number is 2.5 just to leave it be and print it as is.

I am pretty new to PHP, and I taught myself from a text book. So, not knowing many ways to do it off hand, I have a lot of trouble when it comes to making my own functions. I really appreciate the help.

Thanks!

m_tt

You could use abs()

echo abs( 2.0 ) . "\n";
echo abs( 2.5 ) . "\n";

tave

I think this little function will do what you want.

<?php

function bath($num){

   $temp = ceil($num); // round to the next highest integer

   if ($temp > $num){ // if there is a *.5
       $temp = number_format($num, 1); // format with one decimal
   }else {
       $temp = number_format($num, 0); // format without decimal
   }

   return $temp;

}

$nbathrooms = 2.5;

echo bath($nbathrooms);

?>

try that and see if it works for you

tave

m@tt;10879989 wrote:
You could use abs()
echo abs( 2.0 ) . "\n";
echo abs( 2.5 ) . "\n";

I am sorry , but how would that do what he wants? abs() will only return the posite value of the number you pass it, a.k.a the magnitude. Is there some sort of trick that i am not aware of?

m_tt

There is no trick. It returns the absolute value. Try it.

<?php
echo abs( 1.0 ) . "\n";
echo abs( 1.5 ) . "\n";
echo abs( 2.0 ) . "\n";
echo abs( 2.5 ) . "\n";
echo abs( 3.0 ) . "\n";
echo abs( 3.5 ) . "\n";
echo abs( 4.0 ) . "\n";
echo abs( 4.5 ) . "\n";
echo abs( 5.0 ) . "\n";
?>

1
1.5
2
2.5
3
3.5
4
4.5
5

tave

ok, but i don't think that's what he is trying to do. He wants to format a number based on whether or not it has a *.5 value at the end. I don't think it has anything to do with the absolute value

nrg_alpha

the use of is_float or is_int could come in handy for detecting the difference between , well, floats and intergers.

Cheers,

NRG

jpoladsky

tave;10879992 wrote:

I think this little function will do what you want.

<?php

function bath($num){

   $temp = ceil($num); // round to the next highest integer

   if ($temp > $num){ // if there is a *.5
       $temp = number_format($num, 1); // format with one decimal
   }else {
       $temp = number_format($num, 0); // format without decimal
   }

   return $temp;

}

$nbathrooms = 2.5;

echo bath($nbathrooms);

?>

try that and see if it works for you

Yes this is what I was looking for! Thank you.

NogDog

Or just cast it to float:

echo (float) $numBathrooms;