Hi , I have been following a tutorial on how to create a RSS feed from my site using php and xml. However I have reached a stumbling block as I'm not very knowledgeable of xml. Everything looks correct but something is causing the error. The error I am stuck at is as follows:
XML Parsing Error: not well-formed
Location: http://www.fourcourtshostel.com/rsstest.php
Line Number 5, Column 15: </item></channel>
-------------------------------------------------^
And here is my code
<?
class RSS
{
public function RSS()
{
require_once ('mysql_connect.php');
}
public function GetFeed()
{
return $this->getDetails() . $this->getItems();
}
private function dbConnect()
{
DEFINE ('LINK', mysql_connect (DB_HOST, DB_USER, DB_PASSWORD));
}
private function getDetails()
{
$detailsTable = "rss_details";
$this->dbConnect($detailsTable);
$query = "SELECT * FROM ". $detailsTable;
$result = mysql_db_query (DB_NAME, $query, LINK);
while($row = mysql_fetch_array($result))
{
$details = '<?xml version="1.0" encoding="ISO-8859-1" ?>
<rss version="2.0">
<channel>
<title>'. $row['title'] .'</title>
<link>'. $row['link'] .'</link>
<description>'. $row['description'] .'</description>
<language>'. $row['language'] .'</language>
<image>
<title>'. $row['image_title'] .'</title>
<url>'. $row['image_url'] .'</url>
<link>'. $row['image_link'] .'</link>
<width>'. $row['image_width'] .'</width>
<height>'. $row['image_height'] .'</height>
</image>';
}
return $details;
}
private function getItems()
{
$itemsTable = "rss_items";
$this->dbConnect($itemsTable);
$query = "SELECT * FROM ". $itemsTable;
$result = mysql_db_query (DB_NAME, $query, LINK);
$items = '';
while($row = mysql_fetch_array($result))
{
$items .= '<item>
<title>'. $row["title"] .'</title>
<link>'. $row["link"] .'</link>
<description><![CDATA['. $row["description"] .']]></description>
</item>';
}
$items .= '</channel>
</rss>';
return $items;
}
}
?>
Any help or suggestions would be greatly appreciated I would really love to know how to do this.
Thanks
